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Sav [38]
3 years ago
13

What is the mass of HCl that would be required to completely react with 5.2 grams of Mg

Chemistry
2 answers:
Helen [10]3 years ago
8 0
Balanced <span>chemical equation :

</span><span>2 HCl + Mg = H2 + MgCl<span>2
</span></span>
2 x 36.5 g ------------- 24.30 g Mg
 Mass HCl g ----------------- 5.2 g Mg

5.2 x 2 x 36.5 / 24.30 =

Therefore:

379.6 / 24.30 => 15.62 g of HCl 

zhenek [66]3 years ago
4 0

Answer : The mass of HCl required will be, 16.06 grams

Explanation : Given,

Mass of Mg = 5.2 g

Molar mass of Mg = 24 g/mole

Molar mass of HCl = 36.5 g/mole

First we have to calculate the moles of Mg.

\text{Moles of }Mg=\frac{\text{Mass of }Mg}{\text{Molar mass of }Mg}=\frac{5.2g}{24g/mole}=0.22moles

Now we have to calculate the moles of HCl.

The given balanced reaction is,

Mg(s)+2HCl(aq)\rightarrow MgCl_2(aq)+H_2(g)

From the balanced reaction we conclude that

As, 1 mole of Mg react with 2 mole of HCl

So, 0.22 moles of Mg react with 0.22\times 2=0.44 moles of HCl

Now we have to calculate the mass of HCl.

\text{Mass of }HCl=\text{Moles of }HCl\times \text{Molar mass of }HCl

\text{Mass of }HCl=(0.44mole)\times (36.5g/mole)=16.06g

Therefore, the mass of HCl required will be, 16.06 grams

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Kc for the reaction N2O4 &lt;=&gt; 2NO2 is 0.619 at 45 degrees C If 50.0g of N2O4 is introduced into an empty 2.10L container, w
Nadya [2.5K]

Answer:

p(N2O4) = 0.318 atm

p(NO2) = 7.17 atm

Explanation:

Step 1: Data given

Kc = 0.619

Temperature = 45.0 °C

Mass of N2O4 = 50.0 grams

Volume = 2.10 L

Molar mass N2O4 = 92.01 g/mol

Step 2: The balanced equation

N2O4 ⇔ 2NO2

Step 3: Calculate moles N2O4

Moles N2O4 = 50.0 grams / 92.01 g/mol

Moles N2O4 = 0.543 moles

Step 4: The initial concentration

[N2O4] = 0.543 moles/2.10 L = 0.259 M

[NO2]= 0 M

Step 5: Calculate concentration at the equilibrium

For 1 mol N2O4 we'll have 2 moles NO2

[N2O4] = (0.259 -x)M

[NO2]= 2x

Step 6: Calculate Kc

Kc = 0.619=  [NO2]² / [N2O4]

0.619 = (2x)² / (0.259-x)

0.619 = 4x² / (0.259 -x)

x = 0.1373  

Step 7: Calculate concentrations

[N2O4] = (0.259 -x)M = 0.1217 M

[NO2]= 2x = 0.2746 M

Step 8: The moles

Moles = molarity * volume

Moles N2O4 = 0.1217 M * 2.10  = 0.0256 moles

Moles NO2 = 0.2746 M * 2.10 = 0.577 moles

Step 9: Calculate partial pressure

p*V = n*R*T

⇒ with p = the partial pressure

⇒ with V = the volume = 2.10 L

⇒ with n = the number of moles

⇒ with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature = 45 °C = 318 K

p = (nRT)/V

p(N2O4) = (0.0256 *0.08206 * 318)/ 2.10

p(N2O4) = 0.318 atm

p(NO2) = (0.577 *0.08206 * 318)/ 2.10

p(NO2) = 7.17 atm

6 0
3 years ago
What is the speed of a man walking for 30 meters and he walked for 5 seconds ​
aliya0001 [1]

Answer:

<h2>6 m/s</h2>

Explanation:

The speed of the man can be found by using the formula

v =  \frac{d}{t}  \\

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v =  \frac{30}{5}  \\

We have the final answer as

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6 0
3 years ago
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Answer:

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Answer:

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Explanation:

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Molar mass of chlorine = (35.5*2)

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Mass = 55.3 g of chlorine.

Number of moles = 55.3/71

= 0.779 moles.

8 0
2 years ago
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