Salts is the correct awnser
Answer:
Answer) The first box represent the budding type of asexual reproduction . In budding due to the cell divison at the particular place in the organism , new individual will produced.
Second picture represent the budding in hydra. Budding is also a asexual reproduction.
Third type of asexual reproduction is found in plants it is vegetative reproduction.
Fourth is Binary fission . This is also a type of asexual reproduction, in which nucleus dicied into two new daughter cell via mitosis.Explanation:
Answer:
B. CH₄
Explanation:
The primary rule in deciding solubilities is, Like dissolves like. That is,
- A polar solute dissolves in a polar solvent.
- A nonpolar solute dissolves in a nonpolar solvent.
C₆H₁₄ is a nonpolar solvent. Its strongest intermolecular forces are London dispersion forces.
CH₄ is a nonpolar solute. It contains only nonpolar C-H bonds, and its strongest intermolecular forces are London dispersion forces.
Molecules of the two compounds can easily intermingle with each other because the attractive forces between them are so small.
A is wrong. H₂O is a highly polar substance. Its molecules are so strongly attracted to each other that they will not dissolve in the C₆H₁₄.
C and D are wrong. Both NaCl and SnS are compounds of a metal and a nonmetal. We would predict them to be ionic solids, at the extreme end of polarity. They will not dissolve in C₆H₁₄.
Calculate the Mr of aspirin, next workout the percentage of H/aspirin
Acquired because you don't inherit a "cut off" finger. You do it yourself.....if your clumsy enough