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Gala2k [10]
3 years ago
7

In a laboratory preparation room one may find a reagent bottle containing 5.0 L of 12 M NaOH. Write a set of instructions for th

e production of 250 mL of 3.5 M NaOH from such a solution.
Chemistry
1 answer:
kari74 [83]3 years ago
3 0

<u>Answer:</u> The volume taken from the reagent bottle must be 72.91 mL

<u>Explanation:</u>

To calculate the volume of concentrated solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated solution  which is the reagent bottle.

M_2\text{ and }V_2 are the molarity and volume of diluted solution which is the solution to be prepared.

We are given:

M_1=12M\\V_1=?mL\\M_2=3.5M\\V_2=250mL

Putting values in above equation, we get:

12\times V_1=3.5\times 250\\\\V_1=72.91mL

Hence, the volume taken from the reagent bottle must be 72.91 mL

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The equilibrium constant for the reaction
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The question is incomplete, here is the complete question:

The equilibrium constant for the reaction

N₂O₄(g)⇌2NO₂ at 2°C is Kc = 2.0

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The image is attached below.

<u>Answer:</u> The system which represents the equilibrium having value of K_c=2.0 is system (b)

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c

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Molarity of the substance is calculated by using the equation:

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For the given images:

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Number of Gray spheres = 8 moles

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Putting values in expression 1, we get:

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  • <u>For b:</u>

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Number of yellow spheres = 8 moles

Putting values in expression 1, we get:

K_c=\frac{(4/1)^2}{(8/1)}\\\\K_c=2

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Number of Gray spheres = 6 moles

Number of yellow spheres = 6 moles

Putting values in expression 1, we get:

K_c=\frac{(6/1)^2}{(6/1)}\\\\K_c=6

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Number of Gray spheres = 2 moles

Number of yellow spheres = 8 moles

Putting values in expression 1, we get:

K_c=\frac{(2/1)^2}{(8/1)}\\\\K_c=\frac{1}{2}

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