You sell small $4 and large candles $6 at a craft fair. You collect $144 selling a total of 28 candles. How many of each type of candle did you sell?
2 answers:
Answer:
12 Small, 16 Large
Step-by-step explanation:
When you do the math of getting 16 large candles and 12 small candles with respects to the price. You get the math of:
(6×16) + (4×12)
96 + 48
144
16 and 12 will make 28 which proves to be correct as 28 candles were sold
There is a simple algebraic solution to this; a system of equations! x = small candles and y = large candles 4x + 6y = 144 x + y = 28 Now there are two ways to solve this; substitution and elimination. Let’s use substitution for practice with the distributive property... 4x + 6y = 144 y = -x + 28 Put the second equation into the first... 4x + 6(-x + 28) = 144 4x - 6x + 168 = 144 -2x + 168 = 144 -2x = -24 x = 12 Plug this into one of the original equations.... 12 + y = 28 y = 16 And there you have it! You sold 12 small candles and 16 large candles.
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The coordinates of points A, B, and C are (5, 4), (–2, 1), and (4, –4), respectively. Which point, B or C, is closer to point A?
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Answer:
The distance between two points (x1,y1) and (x2,y2) = √((x1-x2)2+(y1-y2)2) Distance between A and B = √((5--2)2+(4-1)2) = √(72+32) = √(49+9) = √58 = 7.62 Distance between A and C = √(12+82) = √65 = 8.06 Point B is closer to A. Another method to solve this problem is to draw the points on a graph paper and measure distance with a ruler.
Answer:
(-20 - 10) / (-12 - (-10))
-30 / -2
30/2
now the midpoint would be half the two points
30/2 ÷ 2/2 = 15/1
So add 15 to -20 (or subtract 15 from 10) for the y, and add 1 to -12 (or subtract 1 from -10) for the x.
Answer:
3x^2 - x - 10
Step-by-step explanation:
Times the two together and you get
3x^2 + (-6x) + 5x + (-10)
Sum these up for your answer