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Citrus2011 [14]
3 years ago
5

Let F(x, y, z) = xi. Let S be the surface given by the quarter of the right-circular cylinder centered on the z-axis, of radius

2 and height 4, which lies in the first octant (use outward-pointing normal).
Let G be the solid in the first octant bounded by S. What is the total flux outward through the four other faces bounding G? Why?
Mathematics
1 answer:
MAXImum [283]3 years ago
8 0

Answer:

ji

Step-by-step explanation:

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4:1

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The exponential function f(x) = 2^x undergoes two transformations to
Eddi Din [679]

Option A: It is vertically stretched

Option B: it is shifted down

Solution:

The exponential function f(x)=2^{x}undergoes two transformations to   g(x)=5 \cdot 2^{x}-3.

<u>To determine how the graph changes:</u>

Consider the given exponential function f(x)=2^{x}.

Let y = f(x)

Vertically compressed or stretched:

A vertically compression (stretched) of a graph is compressing the graph toward x-axis.

• if k > 1 , then the graph y = k• f(x) , the graph will be vertically stretched by multiplying each y coordinate by k.

• if 0 < k < 1 if 0 < k < 1 , the graph is f(x) vertically shrunk (or compressed) by multiplying each of its y-coordinates by k.  

• if k should be negative, the vertical stretch or shrink is followed by a reflection across the x-axis.  

Here, k = 5  

So the graph will be vertically stretched.

Also, Adding 3 to the graph will move the graph 3 units down so, the graph is shifted down.

So, The graph is shifted down.  

Hence option A and option B is the correct answer.

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