The direct distance form A to C is represented by the inequality
AC < 40 yards.
<h3>What is a Triangle ?</h3>
A triangle is a polygon with three sides , three vertices and three angles.
It is given that
Distance form point A to B is 15 yards
Distance form point B to C is 25 yards.
Distance AC = ?
In a Triangle the sum of two sides is always greater than the third side.
Therefore
AC < 15 +25
AC < 40 yards.
Therefore the direct distance form A to C is represented by the inequality AC < 40 yards.
To know more about Triangle
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Answer:
![Pr = 6.67\%](https://tex.z-dn.net/?f=Pr%20%3D%206.67%5C%25)
Step-by-step explanation:
Given
i.e. 10 people
Required
Probability of being next to each other
First, we calculate the total possible arrangements (without any restriction)
![Total = n!](https://tex.z-dn.net/?f=Total%20%3D%20n%21)
![Total = 10!](https://tex.z-dn.net/?f=Total%20%3D%2010%21)
If the three are to be next to each other,
First, we arrange the three
![r_1 = 3!](https://tex.z-dn.net/?f=r_1%20%3D%203%21)
Now, the 3 will be seen as 1; so, we have a total of 8 people i.e. (1 + 7 others)
The arrangement is:
![r_2 =8!](https://tex.z-dn.net/?f=r_2%20%3D8%21)
So, the total arrangement, when they have to be next to one another is:
![r = r_1 * r_2](https://tex.z-dn.net/?f=r%20%3D%20r_1%20%2A%20r_2)
![r = 3! * 8!](https://tex.z-dn.net/?f=r%20%3D%203%21%20%2A%208%21)
The probability is:
![Pr = \frac{r}{n}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7Br%7D%7Bn%7D)
![Pr = \frac{3! * 8!}{10!}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B3%21%20%2A%208%21%7D%7B10%21%7D)
Expand
![Pr = \frac{3*2*1 * 8!}{10*9*8!}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B3%2A2%2A1%20%2A%208%21%7D%7B10%2A9%2A8%21%7D)
![Pr = \frac{3*2*1}{10*9}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B3%2A2%2A1%7D%7B10%2A9%7D)
![Pr = \frac{6}{90}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B6%7D%7B90%7D)
![Pr = 0.0667](https://tex.z-dn.net/?f=Pr%20%3D%200.0667)
Express as percentage
![Pr = 0.0667 * 100\%](https://tex.z-dn.net/?f=Pr%20%3D%200.0667%20%2A%20100%5C%25)
![Pr = 6.67\%](https://tex.z-dn.net/?f=Pr%20%3D%206.67%5C%25)
Answer:
a) positive direction: t < 2s & t>6s ; negative direction: 2s < t < 6s
b) 7 m
c) 71 m
Step-by-step explanation:
Given:
v(t) = 3t^2 -24t +36 [0 , 7]
Find:
a) The value of time when particle is moving in positive direction:
The change in direction of the particle can be determined by v(t) > 0
Hence,
0 < 3t^2 -24t +36
0 < t^2 - 8t + 12
0 < (t - 2)*(t - 6)
t < 2s , t > 6s
The particle travels in positive direction in the interval t < 2s and t > 6s , While it travels in negative direction when 2s < t < 6s.
b) The displacement ds over the given interval [ 0 , 7 ]
ds = integral (v(t)).dt
ds = t^3 -12t^2 +36t
ds = 7^3 -12*7^2 +36*7
ds = 7 m
c) Total distance traveled in the interval:
Total distance= ds(0-2) + ds(2-6) + ds(6-7)
D = 2*(2^3 -12*2^2 +36*2) - 2*(6^3 -12*6^2 +36*6) + 7
D = 2*32 - 2*0 + 7
D = 71 m
Answer:
H = 142
Step-by-step explanation:
H - 35 = 107
+35 +35
H = 142