Answer:
- 1/3
- y-axis
- (1, -2)
Step-by-step explanation:
The length AC is 3, but the corresponding length FD is 1, so the dilation factor is FD/AC = 1/3.
The reflection is a left/right reflection, so it is across a vertical line. We suspect the only vertical line you are interested in is the y-axis. (It could be reflected across x=1/2, and then the only translation would be downward.)
The above transformations will put C' at (1, 0). Since the corresponding point D is at (2, -2), we know it is C' is translated by (1, -2) to get to D.
C' + translation = D
(1, 0) +(1, -2) = (2, -2)
Answer:
Option B k > 0
Step-by-step explanation:
we know that
Observing the graph
The slope of the line is positive
The y-intercept is negative
we have
![3y-2x=k(5x-4)+6\\ \\3y=5kx-4k+6+2x\\ \\3y=[5k+2]x+(6-4k)\\ \\y=\frac{1}{3}[5k+2]x+(2-\frac{4}{3}k)](https://tex.z-dn.net/?f=3y-2x%3Dk%285x-4%29%2B6%5C%5C%20%5C%5C3y%3D5kx-4k%2B6%2B2x%5C%5C%20%5C%5C3y%3D%5B5k%2B2%5Dx%2B%286-4k%29%5C%5C%20%5C%5Cy%3D%5Cfrac%7B1%7D%7B3%7D%5B5k%2B2%5Dx%2B%282-%5Cfrac%7B4%7D%7B3%7Dk%29)
The slope of the line is equal to
![m=\frac{1}{3}[5k+2]](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B1%7D%7B3%7D%5B5k%2B2%5D)
Remember that the slope must be positive
so

The value of k is greater than -2/5
Analyze the y-intercept

1.5 is greater than zero
so
the solution for k is the interval ------> (1.5,∞)
therefore
must be true
k > 0
If you would like to solve (g ° f)(x), you can
calculate this using the following steps:<span>
(g ° f)(x) = g(f(x))
(g ° f)(x) = g(f(x)) = g(3x) = 2 * 3x = 6x
<span>The correct result would be 6x.</span></span>
Answer:
The difference of the degrees of the polynomials p (x) and q (x) is 1.
Step-by-step explanation:
A polynomial function is made up of two or more algebraic terms, such as p (x), p (x, y) or p (x, y, z) and so on.
The polynomial’s degree is the highest exponent or power of the variable in the polynomial function.
The polynomials provided are:

The degree of polynomial p (x) is:

The degree of polynomial q (x) is:

The difference of the degrees of the polynomials p (x) and q (x) is:

Thus, the difference of the degrees of the polynomials p (x) and q (x) is 1.
Answer: 6928
----------------------------------------------------------
Explanation:
We have two areas we need to find: The area of the trapezoid and the area of the rectangle. Let's call these areas A1 and A2.
Area of Trapezoid = (height)*(base1+base2)/2
A1 = h*(b1+b2)/2
A1 = 80*(150+100)/2
A1 = 80*250/2
A1 = 20000
A1 = 10000
Area of Rectangle = (length)*(width)
A2 = L*W
A2 = 48*64
A2 = 3072
Subtract the two areas (A1-A2) to get the difference D
D = A1 - A2
D = 10000 - 3072
D = 6928
This difference D is exactly equal to the shaded area.