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2 years ago

What term best describes the geologic event taking place in the above illustration?

Physics

2 answers:

grigory [225]2 years ago

8 0

u lying you made me get it wrong, for ya'll out there who want the real answer is sea floor spreading

Sunny_sXe [5.5K]2 years ago

6 0

Answer:

seafloor spreading

Explanation:

For study island

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A log with a mass of 90.0 kg falls off a cliff with a height of 31.2 m cliff. Assume g = 9.8 ms-2 What energy transformation occ

Vsevolod [243]

Answer:

kinetic energy

Explanation:

8 0

2 years ago

What's the value of 1,152 Btu in joules? A. 1,964,445 J B. 2,485,664 J C. 987,875 J D. 1,215,360 J

OLga [1]

Answer: Option (d) is correct.

Explanation:

Given, 1,152 British thermal units

1 British thermal unit = 1055.06 joules

So, in 1,152 British thermal units there will be :

$1152\times 1055.06 Joules=1215429.12 Joules=1.21542912\times 10^{8} Joules$

Hence, from the given options the closest answer is of option (d). So, option (d) is correct.

4 0

2 years ago

Read 2 more answers

Three masses (3 kg, 5 kg, and 7 kg) are located in the xy-plane at the origin, (2.3 m, 0), and (0, 1.5 m), respectively.

Artist 52 [7]

Answer:

a) C.M $=(\bar x, \bar y)=(0.767,0.7)m$

b) $(x_4,y_4)=(-1.917,-1.75)m$

Explanation:

The center of mass "represent the unique point in an object or system which can be used to describe the system's response to external forces and torques"

The center of mass on a two dimensional plane is defined with the following formulas:

$\bar x =\frac{\sum_{i=1}^N m_i x_i}{M}$

$\bar y =\frac{\sum_{i=1}^N m_i y_i}{M}$

Where M represent the sum of all the masses on the system.

And the center of mass C.M $=(\bar x, \bar y)$

Part a

$m_1= 3 kg, m_2=5kg,m_3=7kg$ represent the masses.

$(x_1,y_1)=(0,0),(x_2,y_2)=(2.3,0),(x_3,y_3)=(0,1.5)$ represent the coordinates for the masses with the units on meters.

So we have everything in order to find the center of mass, if we begin with the x coordinate we have:

$\bar x =\frac{(3kg*0m)+(5kg*2.3m)+(7kg*0m)}{3kg+5kg+7kg}=0.767m$

$\bar y =\frac{(3kg*0m)+(5kg*0m)+(7kg*1.5m)}{3kg+5kg+7kg}=0.7m$

C.M $=(\bar x, \bar y)=(0.767,0.7)m$

Part b

For this case we have an additional mass $m_4=6kg$ and we know that the resulting new center of mass it at the origin C.M $=(\bar x, \bar y)=(0,0)m$ and we want to find the location for this new particle. Let the coordinates for this new particle given by (a,b)