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3 years ago

What term best describes the geologic event taking place in the above illustration?

Physics

2 answers:

grigory [225]3 years ago

8 0

u lying you made me get it wrong, for ya'll out there who want the real answer is sea floor spreading

Sunny_sXe [5.5K]3 years ago

6 0

Answer:

seafloor spreading

Explanation:

For study island

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A plane is heading south with a velocity of 150 kilometers/hour. It experiences a tailwind with a velocity of 20 kilometers/hour

Tatiana [17]

The tailwind speed would actually add up to the speed of the plane.

It would blow from behind the tail of the plane.

Resultant Velocity = 20 km/h + 150 km/h = 170 km/h

6 0

3 years ago

Read 2 more answers

As a person pushes a box across a floor, the energy from the person's moving arm is transferred to the box, and the box and the

Allushta [10]

Answer:

isnt heat transfer

Explanation:

sorry if im wrong

7 0

3 years ago

1.Narysuj obraz ołówka o długości 6 cm znajdującego się w odległości 8 cm od soczewki o ogniskowej 6 cm

Aliun [14]

Answer:

free quotes from carpet repair contractors at door in

Explanation:

india is the most powerful and I have seen a great deal in hindi for girl in a world of sentence since the poem was a novel that led

5 0

3 years ago

Practice questions, will mark brainliest!

andrew-mc [135]

Answer:

266.67Watts

Explanation:

Time = 2.5hr to seconds

3600s = 1hr

2.5hrs = 3600×2.5= 9000s

Force = 32N

Distance = 75km to m

1000m = 1km

75km = 1000×75 = 75000m

Power = workdone / time

Work = force × distance

Therefore work = 32N × 75000m

Work = 2400000Nm

Power = work ➗ time

Power = 2400000Nm ➗ 9000s

Power = 266.67Watts

Watts is the S. i unit of power

I hope this was helpful, please mark as brainliest

4 0

3 years ago

A basketball player grabbing a rebound jumps 76.0 cm vertically. How much total time (ascent and descent) does the player spend.

MatroZZZ [7]

Answer: Part(a)=0.041 secs, Part(b)=0.041 secs

Explanation: Firstly we assume that only the gravitational acceleration is acting on the basket ball player i.e. there is no air friction

now we know that

a=-9.81 m/s^2 ( negative because it is pulling the player downwards)

we also know that

s=76 cm= 0.76 m ( maximum s)

using kinetic equation

$v^2=u^2+2as$

where v is final velocity which is zero at max height and u is it initial

hence

$u^2=-2(-9.81)*0.76$

$u=3.8615 m/s\\$

now we can find time in the 15 cm ascent

$s=ut+0.5at^2$

$0.15=3.861*t+0.5*9.81t^2\\$

using quadratic formula

$t=\frac{-3.861+\sqrt{3.86^2-4*0.5*9.81(-0.15)} }{2*0.5*9.81}$

t=0.0409 sec

the answer for the part b will be the same

To find the answer for the part b we can find the velocity at 15 cm height similarly using

$v^2=u^2+2as$

where s=0.76-0.15

as the player has traveled the above distance to reach 15cm to the bottom

$v^2=0^2 +2*(9.81)*(0.76-0.15)$

$v=3.4595$

when the player reaches the bottom it has the same velocity with which it started which is 3.861

hence the time required to reach the bottom 15cm is

$t=\frac{3.861-3.4595}{9.81}$

t=0.0409

8 0

3 years ago