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konstantin123 [22]
3 years ago
5

Suppose the Sun appeared to you 900 times dimmer than it does now. How far away from the Sun would you be? (A) 1/9 AU (B) 3 AU

(C) 30 AU (D) 90 AUs (E) 900 AUs
Physics
1 answer:
Harrizon [31]3 years ago
5 0

Answer:

The correct answer is option 'c': 30 AUs

Explanation:

For a spherical wave front emitted by sun with total energy 'E' the energy density over the surface when it is at a distance 'r' from the sun is given by

e=\frac{E}{4\pi r^{2}}

This energy per unit area is sensed by observer as intensity of the sun.

Let the initial intensity of sun at a distance r_{1} be e_{1}

Thus if the sun becomes 900 times dimmer we have

e'=\frac{e_{1}}{900}\\\\\frac{E}{4\pi r_{2}^{2}}=\frac{1}{900}\times \frac{E}{4\pi r_{1}^{2}}\\\\\Rightarrow r_{2}^{2}={r_{1}^{2}}\times 900\\\\\therefore r_{2}={r_{1}}\times {30}

Thus the distance increases 30 times.

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  • <u><em>(b) 1:1</em></u>

Explanation:

<u></u>

<u>1. Formulae:</u>

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  • λ = h/(mv)
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  • λ = de-Broglie wavelength
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<u><em>2. Reasoning</em></u>

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A proton has mass number 1.

Thus, the relative masses of an alpha particle and a proton are:

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