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sashaice [31]
3 years ago
7

In a 120-volt circuit having a resistance of 12 ohms, the power W in watts when a current I is flowing through is given by W=120

I−12I². What is the maximum power, in watts, that can be delivered in this circuit?
Physics
1 answer:
Mrac [35]3 years ago
5 0

Answer:

maximum power = 300 W

Explanation:

Ohm's law: Ohm's law state that the current flowing through a metallic conductor, is directly proportional to the potential difference applied across its end. mathematically it is expressed as,

V = IR............. Equation 1

Where V = potential difference, I = current, R = Resistance of the conductor.

If the power flowing through is gives as

W = 120I - 12I² ..................... Equation 2

To get the maximum power we differentiate of equation 2  and equate to zero

dW/dt = 0

120 - 24l = 0........................... equation 3

Making I the subject of the equation,

I = 120/24 = 5 A.

Suubstituting the value of I into Equation 2

W = 120 (5) - 12(5)²

W = 600 - 300

W = 300 W.

Therefore maximum power = 300 W

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11 rev/20s = 0.55 rev/s = f

then we have:

w = 2*pi*0.55 s^-1 = 2*3.14*0.55 s^-1 = 3.454 s^-1

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yawa3891 [41]

Answer:

a) α = 9.30 rad / s²  and b) t = 2.26 s

Explanation:

Part A

For this exercise we will use the equation of Newton's second law rotational

     Σ τ = I α

     fr r = I α

Where I is the moment of inertia of the sphere

     I = 2/5 M r²

We replace

    fr r = 2/5 M r² α

    α = 5/2 fr / M r

Let's calculate

    M = 250 g (1 kg / 1000g) = 0.250 kg

    r = d / 2 = 4.30 / 2

    r = 2.15 cm (1m / 100cm) = 0.0215 m

   

    α = 5/2 0.0200 / (0.250 0.0215)

    α = 9.30 rad / s²

Part B

Let's use the angular kinematic equation

    w = w₀ - α t

    t = (w - w₀) / α

They give us the change in angular velocity 21.0 ras / s

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