Answer:
The weight of the probe is 50 Newtons
Explanation:
Newtons second law states that F = ma
Given the mass of 25kg, and the acceleration of 2m/s^2, we can substitute both values into the equation to find the weight force.
![F = ma](https://tex.z-dn.net/?f=F%20%3D%20ma)
![F = 25 * 2](https://tex.z-dn.net/?f=F%20%3D%2025%20%2A%202)
![F = 50N](https://tex.z-dn.net/?f=F%20%3D%2050N)
The weight of the probe is 50 Newtons
Answer:
a. The station is rotating at ![1.496 \frac{rev}{min}](https://tex.z-dn.net/?f=%201.496%20%5Cfrac%7Brev%7D%7Bmin%7D)
b. the rotation needed is ![2.8502 \frac{rev}{min}](https://tex.z-dn.net/?f=%202.8502%20%5Cfrac%7Brev%7D%7Bmin%7D)
Explanation:
We know that the centripetal acceleration is
![a_{c}= \omega ^2 r](https://tex.z-dn.net/?f=a_%7Bc%7D%3D%20%5Comega%20%5E2%20r)
where
is the rotational speed and r is the radius. As the centripetal acceleration is feel like an centrifugal acceleration in the rotating frame of reference (be careful, as the rotating frame of reference is <u>NOT INERTIAL,</u> the centrifugal force is a fictitious force, the real force is the centripetal).
<h3>a. </h3>
The rotational speed is :
![2.7 \frac{m}{s^2} = \omega ^2 * 110 \ m](https://tex.z-dn.net/?f=2.7%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%20%3D%20%5Comega%20%5E2%20%2A%20110%20%20%5C%20m)
![\omega ^2 = \frac{2.7 \frac{m}{s^2}} {110 \ m}](https://tex.z-dn.net/?f=%20%5Comega%20%5E2%20%3D%20%5Cfrac%7B2.7%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%7D%20%7B110%20%5C%20m%7D%20)
![\omega = \sqrt{ 0.02454 \frac{rad^2}{s^2} }](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%20%5Csqrt%7B%200.02454%20%5Cfrac%7Brad%5E2%7D%7Bs%5E2%7D%20%7D%20)
![\omega = 0.1567 \frac{rad}{s}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%200.1567%20%5Cfrac%7Brad%7D%7Bs%7D%20%20)
Knowing that there are
in a revolution and 60 seconds in a minute.
![\omega = 0.1567 \frac{rad}{s} \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%200.1567%20%5Cfrac%7Brad%7D%7Bs%7D%20%20%5Cfrac%7B1%20%5C%20rev%7D%7B2%5Cpi%20%5C%20rad%7D%20%5Cfrac%7B60%20%5C%20s%7D%7B1%20%5C%20min%7D)
![\omega = 1.496 \frac{rev}{min}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%201.496%20%5Cfrac%7Brev%7D%7Bmin%7D)
<h3>b. </h3>
The rotational speed needed is :
![9.8 \frac{m}{s^2} = \omega ^2 * 110 \ m](https://tex.z-dn.net/?f=9.8%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%20%3D%20%5Comega%20%5E2%20%2A%20110%20%20%5C%20m)
![\omega ^2 = \frac{9.8 \frac{m}{s^2}} {110 \ m}](https://tex.z-dn.net/?f=%20%5Comega%20%5E2%20%3D%20%5Cfrac%7B9.8%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%7D%20%7B110%20%5C%20m%7D%20)
![\omega = \sqrt{ 0.08909 \frac{rad^2}{s^2} }](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%20%5Csqrt%7B%200.08909%20%5Cfrac%7Brad%5E2%7D%7Bs%5E2%7D%20%7D%20)
![\omega = 0.2985 \frac{rad}{s}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%200.2985%20%5Cfrac%7Brad%7D%7Bs%7D%20%20)
Knowing that there are
in a revolution and 60 seconds in a minute.
![\omega = 0.2985 \frac{rev}{min} \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%200.2985%20%5Cfrac%7Brev%7D%7Bmin%7D%20%20%5Cfrac%7B1%20%5C%20rev%7D%7B2%5Cpi%20%5C%20rad%7D%20%5Cfrac%7B60%20%5C%20s%7D%7B1%20%5C%20min%7D%20)
![\omega = 2.8502 \frac{rev}{min}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%202.8502%20%5Cfrac%7Brev%7D%7Bmin%7D)
Answer:
Their number should increase
Explanation:
The photoelectric effect is a phenomenon that causes the ejection of electrons from that metal as light shined onto a metal surface. Only certain frequencies of light can cause the ejection of electrons. However, if the frequency of the incident light is too low then no electrons were ejected even if the intensity of the light was very high. If the frequency of the light was higher then electrons were able to be ejected from the metal surface even if the intensity of the light was very low.
According to the accepted wave theory, light of any frequency will cause electrons to be emitted. Kinetic energy emitted by the electrons depends upon the intensity of light.
According to the accepted wave theory, number of electrons being ejected by the metal should increase
We are
given that:
m = 5.5 kg
d = 12 m
t = 1.75 s
Using the
distance formula, we can get the acceleration of the ball:
d = (1/2) a*t^2
Rearranging:
a = 2d/t^2
= 2*(12 m)/(1.75 s)^2
a = 7.837
m/s^2
<span>Using
Newton’s 2nd law, force is defines as:</span>
F = ma
F = 5.5 kg
(7.837 m/s^2)
<span>F = 43.10
N</span>
Metals have a larger number of loose electrons, while the electrons in glass and ceramics are packed tighter. Electricity is a flow of electrons, so looser electrons allow an easier flow.