Answer:
426.84 m
Explanation:
initial velocity u = 0
time t = 3.3 s
distance travelled s = 53.4 m
acceleration due to gravity = g
s = ut + 1/2 g t²
53.4 = 0 + 1/2 g x 3.3²
g = 9.8 m /s²
For the whole length of fall
distance travelled = h
total time = 6.6 + 3.3 = 9.9 s
h = ut + 1/2 g t²
u again = 0
h = .5 x 9.8 x 9.9²
= 480.24 m
distance travelled in last 6.6 s
= 480.24 - 53.4
= 426.84 m
Answer:
Explanation:
From the diagram affixed below completes the question
Now from the diagram; We need to resolve the force at point A into (3) components ; i.e x.y. & z directions which are equivalent to 
So;
= positive x axis
Negative y axis
= positive z axis
Then;
From equation (1); Let's make 
the subject of the formula ; then :
Substituting the value for into equation (2) ; we have:
You would benefit from your own handled problem because you solved a problem you had.
i’m pretty sure that’s it, going off the info i had.
Answer:
Explanation:
Force constant of spring K = 21 N /m
we shall find the common velocity of putty-block system from law of conservation of momentum .
Initial momentum of putty
= 5.3 x 10⁻² x 8.97
= 47.54 x 10⁻² kg m/s
If common velocity after collision be V
47.54 x 10⁻² = ( 5.3x 10⁻² + .454) x V
V = .937 m/s
If x be compression on hitting the putty
1/2 k x² = 1/2 m V²
21 x² = ( 5.3x 10⁻² + .454) x .937²
x² = .0212
x = .1456 m
14.56 cm
Answer:
4.096 kW
Explanation:
Applying,
P = Fvcos∅................. Equation 1
Where P = Power of the motor, F = Force exerted on the motor, v = Velocity, ∅ = angle.
From the question,
Given: F = 500 N, v = 10 m/s, ∅ = 35°
Substitute these values into equation 1
P = 500×10×cos35°
P = 4095.8 W
P = 4.096 kW
Hence the power rating of the moto in kW is 4.096 kW
