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3 years ago

The question is: type your equation for the following pattern

Mathematics

1 answer:

Nana76 [90]3 years ago

7 0

Answer:

$\large\boxed{a(n)=16\left(\dfrac{1}{2}\right)^{n-1}}$

Step-by-step explanation:

$a(1)=16\\\\a(2)=16:2=8\\\\a(3)=8:2=4\\\\a(4)=4:2=2\\\\a(5)=2:2=1\\\\a(n)=a_{n-1}:2=\dfrac{1}{2}a_{n-1}$

This is a geometric series with the common ratio $r=\dfrac{1}{2}$ and the first term $a_1=16$ .

An explicit formula of the n-th term of a geometric sequence:

$a_n=a_1r^{n-1}$

Substitute:

$a_n=16\left(\dfrac{1}{2}\right)^{n-1}$

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Which statement is true?

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<h2>Hello!</h2>

The answer is:

The second option,

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Discarding each given option in order to find the correct one, we have:

<h2>First option,</h2>

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[2m]{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[m]{xy}$

<h2>Second option,</h2>

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

The statement is true, we can prove it by using the following properties of exponents:

$(a^{b})^{c}=a^{bc}$

$\sqrt[n]{x^{m} }=x^{\frac{m}{n} }$

We are given the expression:

$(\sqrt[m]{x^{a} } )^{b}$

So, applying the properties, we have:

$(\sqrt[m]{x^{a} } )^{b}=(x^{\frac{a}{m}})^{b}=x^{\frac{ab}{m}}\\\\x^{\frac{ab}{m}}=\sqrt[m]{x^{ab} }$

Hence,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

<h2>Third option,</h2>

$a\sqrt[n]{x}+b\sqrt[n]{x}=ab\sqrt[n]{x}$

The statement is false, the correct form of the statement (according to the property of roots) is:

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<h2>Fourth option,</h2>

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The statement is false, the correct form of the statement (according to the property of roots) is:

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=\sqrt[m]{\frac{x}{y} }$

Hence, the answer is, the statement that is true is the second statement:

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