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3 years ago

If both the numerator and denominator of 48/64 are divided by 8, the fraction will be in lowest terms. True False

Mathematics

2 answers:

Luda [366]3 years ago

6 0

Answer:

If 48/64 are both divided by 8 you would get 6/8, these can still be reduced to 3/4, So the answer should be false. I am sorry if i am wrong tho

Step-by-step explanation:

Licemer1 [7]3 years ago

4 0

If 48/64 are both divided by 8 you would get 6/8! these can still be reduced to 3/4, So FALSE!

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The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

3 years ago

P-6= -5 can u slove this equation plx

torisob [31]

So u have to solve for p to do that you must isolate p by moving -6 after the equal sign -5+6=1 and there is the answer: 1 hope this helps!!

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3 years ago

What is the greatest common factor of 3x^4, 15x^3", and 21x^2??

Umnica [9.8K]

Answer:3x^2 each coefficient is divisible by 3 and and you can take x^2 from both of them

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2 years ago

What is the present value of $6,000 to be received at the end of each of eight periods, assuming the first payment occurs at the

Kipish [7]

Answer: Present value = $7200

Step-by-step explanation: Given Principal that is the original amount is $6000

Rate is 10% every fourth year

But the total period is eight.

So the interest would be paid 8/4 = 2 times.

Therefore,

Simple interest

= {principal * rate * no of times}/100

= {$6000*10*2}/100

Simple interest = $1200

Present value

= principal + Simple interest

= $6000 + $1200

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3 years ago

∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices A'(-1, 1), B'(-2, -1), C(-1, 0). What are the vertices of

blsea [12.9K]

Hi there!
Reflections across the line y = -x always go by the rule (-y, -x). We can use this rule to get our answer here. We are given the aftermath of the reflection coordinates, which are A'(-1, 1), B'(-2, -1), and C'(-1, 0). All we have to do now is switch up the coordinate values and multiply them by -1. Here is the work -
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3 years ago

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