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Hitman42 [59]
3 years ago
14

Solve a/10 - 1/2=1/2 for a

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
6 0

Answer: a=10

Step-by-step explanation:

1. You have the following equation given in the problem above:

\frac{a}{10}-\frac{1}{2}=\frac{1}{2}

2. You must add 1/2 to both side of the equation, then:

\frac{a}{10}-\frac{1}{2}+\frac{1}{2}=\frac{1}{2}+\frac{1}{2}\\\frac{a}{10}=1

3. Now, you must multiply each side of the equation given by 10, therefore, you obtain the following result:

\frac{a}{10}*10=1*10\\a=10

tankabanditka [31]3 years ago
6 0

Answer:

a=10

Step-by-step explanation:

The given equation is

\frac{a}{10}-\frac{1}{2}=\frac{1}{2}

Group similar terms to get;

\frac{a}{10}=\frac{1}{2}+\frac{1}{2}

This implies that;

\frac{a}{10}=1

We multiply both sides by 10 to get;

a=1\times 10

\Rightarrow a=10

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13.54 +2.063 +0.14 +52.1= 67.843
so the answer is D.
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3 years ago
What is the solution to the system of equations? you must show all work to recieve full credit!
earnstyle [38]
Use the substitution method:
2x - 6y = -12
x - 2y = -8
Then x = 2y - 8
Substitute in the first equation:
2(2y - 8) - 6y = -12
4y - 16 - 6y = -12
-2y = 4
y = -2
Now substitute y in one of the two equations given you prefer:
For example x-2*(-2) = -8
x + 4 = -8
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5 0
3 years ago
LMN is a right-angle triangle. Angle NLM=90. PQ is parallel to LM. The area of triangle PNQ is 8cm^2. The area of triangle LPQ i
likoan [24]

Answer:

The area of LQM is 48cm^2

Step-by-step explanation:

Given

Area of PNQ = 8

Area of LPQ = 16

See attachment for triangles

The area of PNQ is calculated as:

Area = \frac{1}{2} * PQ * PN

Substitute 8 for Area

8 = \frac{1}{2} * PQ * PN

PQ * PN = 16

The area of LPQ is calculated as:

Area = \frac{1}{2} * PQ * LP

Substitute 16 for Area

16= \frac{1}{2} * PQ * LP

From the attachment:

PN + LP =LN

Make LP the subject

LP = LN -PN

So:

16= \frac{1}{2} * PQ * (LN -PN)

We have:

16= \frac{1}{2} * PQ * (LN -PN) and PQ * PN = 16

Equate both expressions:

\frac{1}{2} * PQ *(LN - PN) = PQ * PN

Divide both sides by PQ

\frac{1}{2} (LN - PN) = PN

Multiply both sides by 2

LN - PN = 2PN

LN= 3PN

Since PNQ is similar to LNM, the following equivalent ratios exist:

\frac{LM}{PQ} = \frac{LN}{PN}

Substitute LN= 3PN

\frac{LM}{PQ} = \frac{3PN}{PN}

\frac{LM}{PQ} = 3

LM = 3PQ

Area of LQM is:

Area = \frac{1}{2} * LM * LP

This gives:

Area = \frac{1}{2} * 3PQ * LP

Area = 3 *\frac{1}{2} *PQ * LP

Recall that:

16= \frac{1}{2} * PQ * LP

So:

Area = 3 *16

Area = 48cm^2

5 0
3 years ago
How I write this problem
makkiz [27]
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If two angles are complementary and one angle measures 89, what is the measure of the other angle?
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Complimentary means they add up to 90

x is the angle we're looking for

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A is the correct answer.
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