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KatRina [158]
3 years ago
10

Solving multi-step 2(8+4c)=32 c=​

Mathematics
1 answer:
professor190 [17]3 years ago
7 0
You’re gonna multiplying & you do that it would be 16+ 8c= 32 and then you subtract 16 from 32 and that gives you 8c = 16 and you dived and C = 2
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If you spend $25 a day ,how long would it take to spend 1000,000
OleMash [197]
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5 0
3 years ago
Determine 4th term in the geometric sequence whose first term is -2 and whose common ration is -5.
anygoal [31]

Answer:

a_{4} = 250

Step-by-step explanation:

To obtain any term in the geometric sequence multiply the previous term by the common ratio r

here r = - 5 and a_{1} = - 2, hence

a_{2} = - 2 × - 5 = 10

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8 0
3 years ago
A projectile is launched from ground level with a initial velocity of Vo feet per second. Neglecting air resistance, its height
antiseptic1488 [7]
The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.

Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s

The projectile reaches a height of  192 ft at 3 s on the way up, and at 4 s on the way down.

Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s

When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.

Answer: 7 s

4 0
3 years ago
A school ends the year with 651 students. This is a 5% increase from the start of the school year.
Jet001 [13]
ANSWER:

n = 1.05n divided by 105 times 100

OR

n = (the number of students at the END of the school year) divided by 105 times 100

WORKING OUT:

1.05n = 651 students
1n = 651/105 times 100 = ANSWER
5 0
3 years ago
Read 2 more answers
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