Ok do 75x150 then 25x40 and then add them together, and ps. do bace x hight
Answer:
= 250
Step-by-step explanation:
To obtain any term in the geometric sequence multiply the previous term by the common ratio r
here r = - 5 and
= - 2, hence
= - 2 × - 5 = 10
= 10 × - 5 = - 50
= - 50 × - 5 = 250
The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.
Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s
The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.
Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s
When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.
Answer: 7 s
ANSWER:
n = 1.05n divided by 105 times 100
OR
n = (the number of students at the END of the school year) divided by 105 times 100
WORKING OUT:
1.05n = 651 students
1n = 651/105 times 100 = ANSWER