If you would like to solve (g ° f)(x), you can
calculate this using the following steps:<span>
(g ° f)(x) = g(f(x))
(g ° f)(x) = g(f(x)) = g(3x) = 2 * 3x = 6x
<span>The correct result would be 6x.</span></span>
Micah did not explain the last step correctly. You cannot cross out a term from the numerator and denominator unless it is a factor. In other words, x² needed to be multiplied and not added in order to cross it out.
Answer:
a) A dozen= 24
3 dozen= 24 x 3
= 72
b) 1 dozen= 12 bananas
A dozen cost= 24
So, 1 banana cost= 24/12
= 2
So, 6 bananas would be 2 x 6 = 12
c) 1 dozen= 12 bananas
A dozen cost= 24
1 banana cost= 24/12
= 2
d) I need to know how many people are there in your class so please mention that first :)
Mark me brainliest pleaseee
Answer:
4x-2x+3y+6x+6y distributive property
4x-2x+6y+3y+6y commutative property of addition
8x+9y combine like terms
Step-by-step explanation:
I hope this helps!
Answer:
a = p * q
b = p * s + q * r
c = r * s
Step-by-step explanation:
In the trinomial ax² + bx + c
a is the coefficient of x²
b is the coefficient of x
c is the numerical term
∵ The trinomial is ax² + bx + c
∵ Its factors are (px + r) and (qx + s)
∴ ax² + bx + c = (px + r)(qx + s)
∵ (px + r)(qx + s) = (px)(qx) + (px)(s) + r(qx) + (r)(s)
∴ (px + r)(qx + s) = pqx² + (psx + qrx) + rs
∴ ax² + bx + c = pqx² + (ps + qr)x + rs
→ By comparing the two sides
∵ ax² = pqx² ⇒ divide both sides by x²
∴ a = pq
∵ bx = (ps + qr)x ⇒ Divide both sides by x
∴ b = ps + qr
∴ c = rs
∴ a = p * q
∴ b = p * s + q * r
∴ c = r * s
