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Agata [3.3K]
3 years ago
5

What is 6÷(2+4) i really need you to get it right, thx!

Mathematics
2 answers:
dedylja [7]3 years ago
7 0

Answer:

The answer is 1

Step-by-step explanation:

(2+4)=6

dividing it by 6 gives you a positive 1

lawyer [7]3 years ago
5 0

Answer:

6÷(2+4)= 6÷8= 3/4

........

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Five and one half of 2 and one third is what number?
labwork [276]

Given:

Five and one half of 2 and one third.

To find:

The number for the given statement.

Solution:

Five and one half = 5\dfrac{1}{2}

2 and one third = 2\dfrac{1}{3}

The given statement is five and one half of 2 and one third.

Here, the word "of" is used for multiplication.

So, the expression for the given statement is:

5\dfrac{1}{2}\times 2\dfrac{1}{3}

=\dfrac{10+1}{2}\times \dfrac{6+1}{3}

=\dfrac{11}{2}\times \dfrac{7}{3}

=\dfrac{77}{6}

Therefore, the required number is \dfrac{77}{6}.

8 0
2 years ago
What is the value of y in the equation 6 + y = −3? (1 point) Group of answer choices −3 −9 3 9
Paraphin [41]

Answer:

y= -9

Step-by-step explanation:

y+6=-3

subtract 6 from both sides

y=-9

4 0
2 years ago
Read 2 more answers
Total profit P is defined as total revenue R minus total cost​ C, and is given by the function P(x)=R(x)−C(x). Find the total pr
satela [25.4K]

Given:

The revenue function is

R(x)=126.98x-0.5x^2

The cost function is

C(x)=3809.40+0.7x^2

To find:

The profit function.

Solution:

We know that, the total profit P is defined as total revenue R minus total cost​ C.

So, the profit function is

P(x)=R(x)-C(x)

P(x)=126.98x-0.5x^2-(3809.40+0.7x^2)

P(x)=126.98x-0.5x^2-3809.40-0.7x^2

P(x)=-3682.42-1.2x^2

Therefore, the profit function is P(x)=-3682.42-1.2x^2.

5 0
3 years ago
Which statement matches the inequality − 2 < 9?
swat32

Answer: Answer is C.

Step-by-step explanation: It is because positive numbers go to the right, and negative numbers to the left.

Hope that helps :)

8 0
3 years ago
Read 2 more answers
The numbers 1,6,8,13,15,20 can be placed in the circle below, each exactly once, so that the sum of each pair of numbers adjacen
kompoz [17]

Answer:

\fbox{\begin{minipage}{4em}36 ways\end{minipage}}

Step-by-step explanation:

<em>Step 1: Re-state the problem in an easier way to set up a permutation problem</em>

"The numbers 1,6,8,13,15,20 can be placed in the circle below, each exactly once, so that the sum of each pair of numbers adjacent in the circle is a multiple of seven"

The series above can be represented again, in form of:

7a + 1, 7b - 1, 7c + 1, 7d - 1, 7e + 1, 7f - 1

with a, b, c, d, e, f are non-negative integers.

=> 3 numbers are multiply of 7 plus 1

=> 3 numbers are multiple of 7 minus 1

<em>Step 2: Perform the counting:</em>

For the 1st number, there are 6 ways to select

To satisfy that each pair of numbers creates a multiple of 7, then:

For the 2nd number, there are 3 ways left to select

For the 3rd number, there are 2 ways left to select

For the 4rd number, there are 2 ways left to select

For the 5th number, there are 1 way left to select

For the 6th number, there are 1 way left to select

=> In total, the number of possible ways to select:

N = 6 x 3 x 2 x 2 x 1 x 1 = 72

However, these numbers are located around a circle, each option is counted twice.

=> The final number of possible ways:

N = 72/2 = 36

Hope this helps!

:)

3 0
3 years ago
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