Arrange from smallest to largest
-25, -12/4, 1/5, 18/5, 10
chose the middle number
1/5
2nd term: 3+8
= 11
3rd term: 11+8
= 19
4th term: 19+8
= 27
5th term: 27+8
= 35
OR
((n-1)x8)+3
3. We can see that
1+100=101
2+99=101
3+98=101
.................
and so on
From 1 to 100, there are 50 pairs that has the sum is 101
Z=101×50=5050
4. We can see that
1-2=-1
3-4=-1
5-6=-1
...........
and so on
There are 10 pairs that has sum is -1
Z= 10×(-1)=-10
Arc length, (s)=(radius, r)(central angle, q)
s=rq
q=s/r
q=4/10
q=2/5, or 0.4 radians