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2 years ago

Which of the following statements is true?

Mathematics

2 answers:

ra1l [238]2 years ago

7 0

Ur answer is B............!!!!!!

Hope its right!!

Studentka2010 [4]2 years ago

5 0

Answer:

Option D is right.

Step-by-step explanation:

Given are four statements and we have to find which one is true.

A) 15 is not a perfect square and hence square root of 15 is not rational. Incorrect.

B) While 15 has irrational root 0.0001 is the square of 0.01 hence the square root of second is rational hence incorrect

C) Since 15 is not a perfect square and hence square root of 15 is not rational. Incorrect

D) The square root of 15 is irrational and the square root of 0.001 is rational.

is the only correct option

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The mass of one methane molecule is 2.7x10^-23gram. Find the mass of 90,000 molecules of methane. Express the answer in scientif

melomori [17]

Answer:

2.43 • 10^-18

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2 years ago

The Super Shop and Save store had 120 gallons of milk placed on the shelf one night. During the next morning's inspection, the m

Sergeeva-Olga [200]

18 gallons of milk had passed the expiration date.

Explanation step by step

Multiply 120x 15%
Turn 15% into a decimal which is 0.15 so now it’s 120x0.15 which equals to 18.

8 0

3 years ago

Hurry please I need help on this

lubasha [3.4K]

5/6-2/5 would be my guess

beacuse i would think the answer would be 1/3 but that is not on the multiple choice.

5 0

2 years ago

The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow

Reika [66]

If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now $\bf \begin{cases}
A=l\cdot w\\\\\
A=3000000\\
----------\\
3000000=l\cdot w\\\\
\frac{3000000}{w}=l
\end{cases}\qquad thus
\\\\\\
P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}
\\\\\\
P=3w+6000000w^{-1}\\\\
-----------------------------\\\\
now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}
\\\\\\
\textit{so the critical points are at }
\begin{cases}
0=w^2\\\\
0=\frac{3w^2-6000000}{w^2}
\end{cases}$

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the $0=w^2\implies 0=w$ so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other

8 0

3 years ago

Can someone please help me

astra-53 [7]

Answer:

square 20 has 44 green squares

square 21 has 45 green squares

Step-by-step explanation:

To solve the problem, we need to observe the cases, and determine/define a rule for each case (odd number of sides, or even number of sides).

For square one, we note that the centre square is shared by two diagonals, so we saved one square from the two diagonals.

The side length is 3 for square 1, 4 for square 2, and so on.

Let

n= square number (1, 2,3...)

L = side length (3,4,5...)

G1(n) = function that gives the number of green squares for square n, n=odd

G2(n) = function that gives the number of green squares for square n, n=even

side length, L=n+2 ................(1)

G1(n) = twice the side length less one, as discussed above

G1(n) = 2L-1 now substitute L=n+2

G1(n) = 2(n+2) -1 simplify

G1(n) = 2n + 3

Check:

for n=1, square 1 has 2*1+3 = 5 green squares ... checks

for n=3, square 3 has 2*3+3 = 9... checks

for n=5, square 5 has 2*5+3 = 13 ....checks

For even squares, it is even easier, because

G2(n) = 2L = 2(n+2)

check:

for n=2, square 2 has 2(2+2) = 8 green squares........checks

for n=4, square 4 has 2(4+2) = 12 green squares........checks.

Fincally, we apply our formula to n=20 and n=21

square 20 : G2(20) = 2(n+2) = 2(20+2) = 44 green quars

square 21 : G1(21) = 2n+3 = 2(21)+3 = 45 green squares

5 0

2 years ago