Answer:
t = 64g
Step-by-step explanation:
This is quite straightforward
Let n be the number of tokens he is charged per game.
88 = 2200 - 33n
33n = 2200 - 88
33n = 2112
n = 2112/33 = 64
Now, we write the relation. The number of tokens t at any point in time is 64 multiplied by the number of games
t = 64g
2x+y=9
3x+5y=19
I will do this problem in 2 ways. I.)Substitution II.)Elimination
Solution I.) Substitution
We can subtract 2x from both sides in the first equation.
y=9-2x
Now we can substitute the y in the second equation with 9-2x
3x+5(9-2x)=19
-7x+45=19
-7x=-26
x=26/7
y=9-2(26/7)=11/7
Solution II.)Elimination
We can multiply both side of first equation by 5 to get a 5y in both equations.
10x+5y=45
Now because both are positive 5y we just need to do simple subtraction of the 2 equation, each side respectively.
(10x+5y)-(3x+5y)=45-19
7x=26
x=26/7
2*26/7+y=9
y=11/7
Ultimately you get the same answer, both are viable methods, some problems are faster with one method but I recommend mastering both since they are very useful.
The answer will be A. 69.22
Hope this helps <3
The number is 21 because 2 is 1 doubled, and 2+1 is 3.
Answer:
And the probability that the first die shows an odd number is 1/2, as is the probability that the second does. Since the dice fall independently, P(both are odd) = P(first is odd)*P(second is odd) = (1/2)*(1/2) = 1/4. Therefore P(at least one is even) = 1 - 1/4 = 3/4.
