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katovenus [111]
4 years ago
10

Please Help! Quickly image below with question

Mathematics
1 answer:
GrogVix [38]4 years ago
4 0

Answer:

12742π Km

Step-by-step explanation:

The length of the rope is the circumference of the circle, that is

C = 2πr ( r is the radius ) Here r = 6371

C = 2π × 6371 = 12742π Km

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(a + b)(a 2 - ab + b 2)
JulsSmile [24]

Answer:

a³ + b³

Step-by-step explanation:

Given

(a + b)(a² - ab + b²)

Each term in the second factor is multiplied by each term in the first factor, that is

a(a² - ab + b²) + b(a² - ab + b²) ← distribute both parenthesis

= a³ - a²b + ab² + a²b - ab² + b³ ← collect like terms

= a³ + b³

4 0
4 years ago
Read 2 more answers
Given the following absolute value function find the range f(x)= |x+5|-8
Flauer [41]
The minimum value for |x+5| is 0, so the minimum for f(x) is 0-8=-8.
There is no maximum for |x+5|, so neither does f(x).
Therefore the range of f(x)=|x+5|-8 is [-8,+inf) in interval notation, or
from -8 to infinity in words.
3 0
3 years ago
5. A tank initially contains 20 lb of salt dissolved in 200-gallon of water. Starting at time t = 0, a solution containing 0.5 l
sladkih [1.3K]

Answer:

(a) Amount of salt as a function of time

A(t)=100-80e^{-0.02t}

(b) The time at which the amount of salt in the tank reaches 50 lb is 23.5 minutes.

(c) The amount of salt when t approaches to +inf is 100 lb.

Step-by-step explanation:

The rate of change of the amount of salt can be written as

\frac{dA}{dt} =rate\,in\,-\,rate\,out\\\\\frac{dA}{dt}=C_i*q_i-C_o*q_o=C_i*q_i-\frac{A(t)}{V}*q_o\\\\\frac{dA}{dt}=0.5*4-\frac{A(t)}{200}*4\\\\\frac{dA}{dt} =\frac{100-A(t)}{50}=-(\frac{A(t)-100}{50})

Then we can rearrange and integrate

\frac{dA}{dt}= -(\frac{A(t)-100}{50})\\\\\int \frac{dA}{A-100}=-\frac{1}{50}  \int dt\\\\ln(A-100)=-\frac{t}{50}+C_0\\\\ A-100=Ce^{-0.02*t}\\\\\\A(0)=20 \rightarrow 20-100=Ce^0=C\\C=-80\\\\A=100-80e^{-0.02t}

Then we have the model of A(t) like

A(t)=100-80e^{-0.02t}

(b) The time at which the amount of salt reaches 50 lb is

A(t)=100-80e^{-0.02t}=50\\\\e^{-0.02t}=(50-100)/(-80)=0.625\\\\-0.02*t=ln(0.625)=-0.47\\\\t=(-0.47)/(-0.02)=23.5

(c) When t approaches to +infinit, the term e^(-0.02t) approaches to zero, so the amount of salt in the solution approaches to 100 lb.

7 0
3 years ago
Explain how to draw a line segments that measures 2 7/16 inches.
boyakko [2]

The line segment which represents 2 7/16 inches should first be drawn with the use of a ruler.

<h3>What is a Ruler?</h3>

This is referred to an instrument which is used to measure distances between points or draw straight lines and also usually graduated in inches.

On the inches graduation, the zero mark should be located and the 1/16 inch which is found before the half-inch mark between 2 and 3 inches. When this is done, a line should be drawn to meet both points which will therefore measure 2 7/16 inches long.

Read more about Ruler here brainly.com/question/18558504

#SPJ1

6 0
2 years ago
A stage designer is making a rectangular drape that is 7 yards in length and 16 yards in width. The fabric for the drape cost $2
USPshnik [31]
Yard to square yard
example: 1yard*1 = 1square yard so 6*6=36 square yards.   7*7=42
36*2.90=104.40
42*2.90=121.8
104.40+121.8=$226.20
6 0
3 years ago
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