Answer:
C
Step-by-step explanation:
-5x-49>113
+49 +49
———————-
-5x>162
—- ——
-5 -5
x<32.4
When we use arcsine, we are finding the angle while giving the trigonometric ratio.
Arcsin(u) = theta can be rewritten as:
sin(theta) = u
Sine is opposite over hypotenuse, so u/1 means that the side opposite to theta (the y value) is u, and the hypotenuse is 1.
We can use Pythagorean Theorem to find the adjacent (x value).
1^2 - u^2 = x^2
x = sqrt(1-u^2)
Back to the original question, we are trying to find cos(arcsin(u)). We just solved all the sides for our triangle using arcsin(u). Now we need to do cos(u).
Cosine is adjacent over hypotenuse.
So our answer is sqrt(1-u^2)/1
Or just sqrt(1-u^2)
Answer:
see explanation
Step-by-step explanation:
A difference of two squares is factored as
a² - b² = (a - b)(a + b)
(g)
1 - 81y²
= 1² - (9y)²
= (1 - 9y)(1 + 9y)
(j)
64x² - 25y²
= (8x)² - (5y)²
= (8x - 5y)(8x + 5y)
The projectile's horizontal and vertical positions at time 
are given by
where 
. Solve 
for the time it takes for the projectile to reach the ground:
In this time, the projectile will have traveled horizontally a distance of
The projectile's horizontal and vertical velocities are given by
At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about 
.
