Question

In a performance test, each of two cars takes 9.0 s to accelerate from rest to 28 m/s. Car A has a mass of 1379 kg, and car B has a mass of 1902 kg. Find the net average force that acts on (a) car A and (b) car B during the test.

Answer 1

Explanation:

It is given that,

Mass of car A, $m_A=1379\ kg$

Mass of car B, $m_B=1902\ kg$

In a performance test, each of two cars takes 9.0 s to accelerate from rest to 28 m/s. Their acceleration is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{28\ m/s}{9}$

a = 3.12 m/s²

(a) The net force of car A, $F_A=m_Aa$

$F_A=1379\ kg\times 3.12\ m/s^2$

$F_A=4302.48\ N$

(b) The net force of car B, $F_B=m_Ba$

$F_B=1902\ kg\times 3.12\ m/s^2$

$F_A=5934.24\ N$

Hence, this is the required solution.