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Tanzania [10]
4 years ago
6

Please answer the number 5 6 and 7. I don't know what to do its our hw in physics. (new lesson as well)

Physics
1 answer:
Aleks04 [339]4 years ago
8 0

From the picture, I see that you had no trouble at all with #4.
Well, #5, 6, and 7 are easily handled in exactly the same way.

Just as you did with #4, please sketch these on paper
as I walk you through the solutions.  That'll help you see
immediately what's going on.

#5.b).
Traveling east at 3 m/s for 4 seconds,
he covers  (3 m/s) x (4 sec) = 12 meters.

Traveling south at 5 m/s for 2 seconds,
he covers (5 m/s) x (2 sec) = 10 meters.

The total distance he covers is  (12m + 10m) = 22 meters.

#5.c).
Average speed (scalar)

                           = (distance covered)/(time to cover the distance)

                           = (22 meters)/(6 sec) = 3-2/3 m/s .

#5.d).
Displacement (vector)

                       = distance between the start-point and the end-point,
                          regardless of the route traveled,
                      
  in the direction from the start-point to the end-point.

Distance from the start-point to the end-point =

               √(12² + 10²) = √(144 + 100) = √(244) = 15.62 meters

in the direction of  arctan(10/12) south of east

                             =  39.8° south of east.
 
#5.e).
Average velocity (vector) =

             (displacement vector) / (time)

         =  15.62 meters directed 39.8° south of east / 6 seconds

         =  2.603 m/s directed 39.8° south of east.

 #6).
Magnitude = √(5.2² + 2.1²) = √(27.04 + 4.41) = √31.45 = 5.608 km.

Direction = arctan(5.2/2.1) south of east

                =   68° south of east  =  158° bearing . 

#7).
Magnitude = √(39² + 57²) = √(1521 + 3249) = √( 4770)

                                                                         =  69.07 m/s .

Direction = arctan (57/39) south of west

               =   55.6° south of west

                    Bearing = 214.4°

                    Compass: 0.65° past "southwest by south".  


I'm grateful for the privilege and opportunity to practice my math,
and I shall cherish the bounty of 5 points that came with it.

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Answer:

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3 years ago
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Answer:

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3 0
3 years ago
What does the 4 mean in 4Cu(NO3)2
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4 years ago
uppose that 3 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 45 cm. (a) How much work i
Lesechka [4]

Answer:

(a) The work done is 0.05 J

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extension of the spring, x = 45 cm - 30 cm = 15 cm = 0.15 m

The work done is given by;

W = ¹/₂kx²

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k = 2W / x²

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k = 266.67 N/m

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work done is given by;

W = ¹/₂kx²

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W = 0.05 J

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F = kx

x = F / k

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7 0
4 years ago
the primary of a transformer connected to 170v has 10 turns. the secondary has 70 turns. find voltage. this is a step down trans
Nikolay [14]
No it isn't. (Unless you connect it backwards.)

If the primary has 10 turns and the secondary has 70 turns,
then the voltage that appears across the secondary is
7 times the voltage that you feed to the primary.

If you're 'exciting' the primary with 170 volts, then you need
to be cautious around the secondary terminals, because there's 
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If you want to use your transformer in a step-down configuration,
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Feed the 170 volts to the winding with 70 turns.  You've reversed
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4 0
4 years ago
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