What is tan for the given triangle?

nasty-shy [4]

Hey there,

<em />Answer:

The sun appears to move across the sky but it is actually the earth which is orbiting around the sun.

Hope this helps :D

<em>~Top</em>

3 0

3 years ago

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n ultraviolet light beam having a wavelength of 130 nm is incident on a molybdenum surface with a work function of 4.2 eV. How f

pashok25 [27]

Answer:

The speed of the electron is 1.371 x 10⁶ m/s.

Explanation:

Given;

wavelength of the ultraviolet light beam, λ = 130 nm = 130 x 10⁻⁹ m

the work function of the molybdenum surface, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

The energy of the incident light is given by;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f = c / λ

$E = \frac{hc}{\lambda} \\\\E = \frac{6.626*10^{-34} *3*10^{8}}{130*10^{-9}} \\\\E = 15.291*10^{-19} \ J$

Photo electric effect equation is given by;

E = W₀ + K.E

Where;

K.E is the kinetic energy of the emitted electron

K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J - 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of the emitted electron is given by;

K.E = ¹/₂mv²

where;

m is mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

$v = \sqrt{\frac{2K.E}{m} } \\\\v = \sqrt{\frac{2*8.563*10^{-19}}{9.11*10^{-31}}}\\\\v = 1.371 *10^{6} \ m/s$

Therefore, the speed of the electron is 1.371 x 10⁶ m/s.

8 0

3 years ago

Ahh ahhh ahhh ahhh ahhh ahhh ahhh ahhh ahhh ahha aggg agg

timama [110]

shhhh hahahaha ahhhhhhhh ahhhh

4 0

3 years ago

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In separate experiments, a large number of particles (all with the same charge but with a wide variety of masses, speeds, and sp

melomori [17]

The particles that move in orbits of the same radius have the same momentum.

<h3>Orbital angular momentum:</h3>

A point particle's three-dimensional angular momentum is traditionally represented by the pseudovector r p, which is the cross product of the particle's position vector r (relative to some origin) and momentum vector, which in Newtonian physics is denoted by p = mv.

L = mr $V_{prep}$ = mr²w is the particle's orbital angular momentum in units of magnitude. The part of the particle's velocity that is here perpendicular to the axis of rotation is designated as $V_{perp.}$ The right-hand rule indicates the direction of the angular momentum. In isolated systems, the angular momentum is conserved.