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Mama L [17]
3 years ago
9

Two parallel, vertical, plane mirrors, 38.8 cm apart, face each other. A light source at point P is 30.1 cm from the mirror on t

he left and 8.7 cm from the mirror on the right.
(a) How many images of point P are formed by the mirrors?
(b) Find the distance from the mirror on the right to the two nearest images behind the mirror.
first nearest image=
second nearest image=
(c) Find the number of reflections of light rays for each of these images.
first nearest image=
second nearest image=
Physics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

Explanation shown below.

Explanation:

1.The number of images formed by 2 parallel mirrors is an infinite number of images.

2. The characteristics of a plane mirror is such that the object distance equals the image distance.

Hence the object distance is 8.7cm from the right; the image formed would be 8.7cm behind the mirror.

Now a second image is going to be formed by the left mirror which is going to have an image distance of 30.1cm behind the mirror.

Now this image would be reflected on the right side to form a new image which is going to be seen as 38.8 +30.1 = 68.9cm behind the right Mirror .

Hence the shortest distances are 8.7cm and 68.9cm

3. The number of reflections is infinite for both cases.

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push or pull

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The chemical energy in your food is transformed into what type of energy in your moving muscles?
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Mechanical energy

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The chemical energy in the food gets changed into the mechanical energy of moving muscles.

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3 years ago
The current in the wires of a circuit is 120.0 milliAmps. If the voltage impressed across the ends of the circuit were doubled (
skad [1K]

Answer:

Its new current will be 240.0milliAmps

Explanation:

According to ohms law,

V = IR

V is the supply voltage in a circuit

I is the current

R is the resistance

If the current in the wires of a circuit is 120.0 milliAmps, the voltage will be:

V1 = 120R1

R1 = V1/120...(1)

If the voltage impressed across the ends of the circuit were doubled (with no change in its resistance),

V2 = 2V1

V2 = IR2

2V1 = IR2

R2 = 2V1/I ... (2)

Since there are no changes in resistance

R1 = R2

Equating 1 and 2, we have:

V1/120 = 2V1/I

1/120 = 2/I

Cross multiplying

I = 2×120

I = 240milliAmps

7 0
3 years ago
Two friends, Barbara and Neil, are out rollerblading. With respect to the ground, Barbara is skating due south at a speed of 3.3
ozzi

Answer:

Answer is invalid make more sense next time please look it up somewhere else or ask somone smart. THere i gave you advice now i get points

Explanation:

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4 years ago
a person carries a plank of wood 2.00 m long with one hand pushing down on it at one end with a force f1 and the other hand hold
yKpoI14uk [10]

The magnitudes of forces at F₁ and F₂ are :

F₁ = 3924 N

F₂ = 4120.2 N

We know that force is the amount of strength required to move a body. The magnitude of force is the sum of all the strengths applied on the body which is exerted by each force together on a particular body.

Given,

Length of plank = 2 m

Force on one end = F₁

Force on the other end = F₂

F₂ is applied to a point which is 0.5 m from the other end

Mass of plank = 20 kg.

Now let us calculate the magnitudes of the forces applied:-

1) Balance of angular momentum around the end where F₁ is applied.

F₂ × 0.5m - F₁ × 0 = mass × g × 1m

⇒ F₂ × 0.5 m= 20 kg × 9.81 m/s² × 1 m = 1,962 N×m

F₂ = 196.2 Nm / 0.5m = 3,924 N

2) Balance of forces

F₁ - F₂ = mg

F₁ = F₂ + mg = 3,924N + 20kg (9.81 m/s²) = 4,120.2 N

Therefore the magnitude of force F₁ is 3924 N and of force F₂ is 4120.2 N.

To know more about force, refer: brainly.com/question/13191643

#SPJ4

3 0
1 year ago
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