Solve for x - 4x + 3 =

maks197457 [2]

To find the median, find the middle number. Since there are 10 numbers, find the 5th one and the 6th one and find their average.

The two numbers are both 9, so its safe to say that the median is 9.

to find the median of the first and quartile, you have to place a line where the median should be and find the median of that. Q1 and Q2 will be 5 and 11 (respectively).

Its easy to see that all the lines start at the lowest point given and end at the largest point given, so match Q1, the median, and Q3

The only line that has lines at the Q1, median, and Q3 we figured out is answer C, so therefore it is the answer.

8 0

3 years ago

A dance studio is purchasing tutus for an annual performance. The table represents the number of tutus available for different p

Ne4ueva [31]

Answer:

30$ C

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Lines CD and CE are tangent to circle a. If m∠DAE = 130°, what is the measure of ∠DCE? Tangent CD intersects with circle A at po

inna [77]

The answer is 50º

Step-by-step explanation:

It is the correct and only plausable answer.

5 0

3 years ago

Read 2 more answers

When n=343 college students are randomly selected and surveyed, it is found that x=110 own a car. Find a 99% confidence interval

Liono4ka [1.6K]

Answer:

The margin of error will be "0.65". A further explanation is provided below.

Step-by-step explanation:

The given values are:

n = 343

x = 110

At 99% confidence level,

$\alpha = 1-99$ %

$=1-0.99$

$=0.01$

then,

$\frac{\alpha}{2} =\frac{0.01}{2}$

$=0.005$

or,

$Z_{\frac{\alpha}{2} }=Z_{0.005}$

$=2.576$

Now,

The point estimate will be:

⇒ $\hat{P}=\frac{x}{n}$

⇒ $=\frac{110}{343}$

⇒ $=0.321$

or,

⇒ $1-\hat{P}=1-0.321$

⇒ $=0.679$

The margin of error will be:

⇒ $E=Z_{\frac{\alpha}{2} }\times \sqrt (\frac{(\hat{P}\times (1 - \hat{P})) }{n} )$

On substituting the above values, we get

⇒ $=2.576\times \sqrt{\frac{0.321\times 0.679}{343} }$

⇒ $=2.576\times \sqrt{\frac{0.217959}{343} }$

⇒ $=0.065$

hence,

⇒ $\hat{P}-E$

⇒ $0.321-0.065$

⇒ $0.256,0.386$

6 0

3 years ago

There are some Nichols dimes and quarters in a large piggy bank for every two nickels there a sweetheart forever to Diane’s ther

grigory [225]

Answer:

There are 80 nickels, 120 dimes and 300 quarters in the piggy bank.

All coins in the piggy bank worth $91.

Step-by-step explanation:

Please consider the complete question:

There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels there are 3 dimes. For every 2 dimes there are 5 quarters. There are 500 coins total. How many nickels, dimes, and quarters are in the piggy bank? Explain your reasoning. How much are the coins in the piggy bank worth?

Let n, d, q represent number of nickles, dimes and quarters respectively.

For every 2 nickels there are 3 dimes. We can represent this information in an equation as:

$\frac{2}{n}=\frac{3}{d}...(1)$ or