I think it’s because they are opposite so Yh sos if it’s wrong
The question wants us to find 3 times the volume of the pool.
This is because we are told that the pool must be filled 3 times during the summer and asked how many cubic feet of water is required to fill the pool all summer.
Step 1: Find the volume of the pool.
Volume is calculated by multiplying length by width by height.
Pool length = 5 ft.
Pool width = 4 ft.
Pool height = 2 ft.
Pool volume = 5 • 4 • 2
5 • 4 • 2 = 40
The volume of the pool is 40 cubic feet.
Step 2: Find 3 times the volume of the pool.
Volume = 40 ft.^3
3 times volume = 3 • 40 ft.^3
3 • 40 ft.^3 = 120 ft.^3
3 times the volume of the pool is 120 cubic feet.
Answer:
The pool requires 120 cubic feet of water in order to be filled enough over the course of the summer.
Hope this helps!
Answer:
3d + 1
I'm pretty sure it's the same thing.
Answer:

Step-by-step explanation:
We have that the polynomial, has a root of multiplicity 2 at x = 3 and a root of multiplicity 1 at x = -2.
This means the factored form of the polynomial will be.

Also, it was given that, the y-intercept is y=-12.6.
This implies that:



Divide both sides by 18;


Therefore the polynomial is

Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.
To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.
Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.
Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.
Therefore:
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 8} \\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%208%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
The nth root of a can contain negative number only if n is an odd number.
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 2 \times - 2 \times - 2} \\ f(4) = 3 \end{cases}} \\ \large{ \begin{cases} f( - 8 ) = - 2\\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%202%20%5Ctimes%20-%20%202%20%5Ctimes%20%20%20-%202%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D%20%5C%5C%20%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20-%202%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
Answer