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liubo4ka [24]
4 years ago
9

I think of a number subtract three then multiply by four

Mathematics
2 answers:
aalyn [17]4 years ago
7 0

Answer:

Step-by-step explanation:

To solve this

We have

Let the number think of b x

Three subtracted from the number will be

x-3

Then multiply by 4

4(x-3)

Open d brackets

4x-12

Artyom0805 [142]4 years ago
4 0

Answer:

4

Step-by-step explanation:

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The function f(x) = One-sixth (two-fifths) Superscript x is reflected across the y-axis to create the function g(x). Which order
Gekata [30.6K]

The ordered pair (-3 , \frac{4}{375} ) is on g(x) ⇒ 1st answer

Step-by-step explanation:

Let us revise the reflection across the axes

  • If the function f(x) reflected across the x-axis, then its image is g(x) = - f(x)  (change the sign of y)
  • If the function f(x) reflected across the y-axis, then its image is g(x) = f(-x)  (change the sign of x)

∵ f(x)=\frac{1}{6}(\frac{2}{5})^{x}

∵ f(x) is reflected across the y-axis to create the function g(x)

- Change the sign of x

∴ g(x)=\frac{1}{6}(\frac{2}{5})^{-x}

To find the point that lies on g(x) substitute x in g(x) by the x-coordinate of the point if the answer equal to the y-coordinate of the point, then the point lies on it if not then the point does not lie on it

∵ The coordinates of the point are (-3 , \frac{4}{375} )

∴ x = -3 and y = \frac{4}{375}

- Substitute x by -3 in g(x)

∵ g(x)=\frac{1}{6}(\frac{2}{5})^{-x}

∴ g(x)=\frac{1}{6}(\frac{2}{5})^{-(-3)}

∴ g(x)=\frac{1}{6}(\frac{2}{5})^{3}

∵ (\frac{2}{5})^{3}=\frac{2^{3}}{5^{3}}=\frac{8}{125}

∴ g(x)=\frac{1}{6}(\frac{8}{125})

∴ g(x)=\frac{8}{750}

- Divide up and down by 2

∴ g(x)=\frac{4}{375}

∵ The value of g(x) equal to the y-coordinate of the point

∴ The point (-3 , \frac{4}{375} ) lies on g(x)

The ordered pair (-3 , \frac{4}{375} ) is on g(x)

Learn more:

You can learn more about the reflection in brainly.com/question/5017530

#LearnwithBrainly

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<u>and/or</u>

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So the zeros are at -1 and 2.


ANSWER: {-1,2}


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V = r²(πh)/3

r² = (3V)/(πh)
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r = √25
r = 5  (but remember the radius is only 1/2 the diameter)

thus . . . 

<u><em>d = 10 in </em></u>
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