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3 years ago

Select the correct answer from each drop-down menu.

Mathematics

2 answers:

Anestetic [448]3 years ago

6 0

Answer:

A. 1. Inner

B.1. Outer

A.2. Mars

B.2. Uranus

Step-by-step explanation:

I had this question on a semester test and i passed the test all 42 questions with a 100. (plato)

olganol [36]3 years ago

4 0

Answer:

Planet A is inner

Planet A is Mars

Planet B is Outer

Planet B is Uranus

Solution:

We know that the inner planets are the planets which are close to the sun. They are relatively small, mostly rocky composition, and have few or no moons.

On other hand, the outer planets are the planets which are far away from the sun. They are mostly huge, ringed, gaseous and have several moons.

In the given problem,

Planet A has rocky mantle and iron core, less no of Moons and no rings, also due to 96% of carbon dioxide, 3% nitrogen and 1% other gases this is denser, and Hence Planet A is inner planet. As the distance from the sun is 1.5 AU and no of moons are 2, hence Planet A is Mars.

On the other hand, Planet B is gaseous with hydrogen and helium gas, hence it is also denser and it has large no of moons and faint rings. So Planet B is Outer planet. As the distance of the planet is 19.22 AU and has 27 moons, hence Planet B is Uranus.

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Which best summmarize the pyhagorean theorem

andre [41]

Answer: the sum of the squares of the lengths of the legs of a right triangle equal the square of the length of the hypotenuse

Step-by-step explanation: hope it helps

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2 years ago

2. Find the value of x. (1 point) (5x) (3x+28) O 14 O20 O 12 O 19

nata0808 [166]

Answer:

x = 14

Step-by-step explanation:

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2 years ago

Show that if X is a geometric random variable with parameter p, then

Lubov Fominskaja [6]

Answer:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

In order to find the expected value E(1/X) we need to find this sum:

$E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}$

Lets consider the following series:

$\sum_{k=1}^{\infty} b^{k-1}$

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

$\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}$ (a)

On the last step we assume that $0\leq r\leq b$ and $\sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}$ , then the integral on the left part of equation (a) would be 1. And we have: