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bagirrra123 [75]
3 years ago
12

Zoé is working two summer making $7 per hour babysitting and making $15 per hour clearing tables. In given week, She can make a

maximum of 14 total hours in must earn at least $130. If Zoe worked 4 hours babysitting, determine all possible values for the number of who I was clearing the tables that she must work to meet her requirements. Your answer should be a comma separate list of values. there are no possible solutions, submit an empty answer
Mathematics
2 answers:
Strike441 [17]3 years ago
8 0
The answer it (7,8,9,10) hours
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

  {7, 8, 9, 10}

Step-by-step explanation:

Having worked 4 hours babysitting, Zoé has already earned 4×$7 = $28, so only needs to earn $130 -28 = $102 more.

At $15 per hour, it takes her $102/$15 = 6.8 hours to earn that amount. In order to keep her total hours to a maximum of 14, Zoé cannot work any table-clearing hours more than 14 -4 = 10. The possible solutions for Zoé's hours doing table clearing are ...

  {7, 8, 9, 10} . . . . hours

_____

We have assumed Zoé must work whole numbers of hours.

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One Endpoint is 9,18 and the midpoint is 14,16 what the other end point
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\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 9}}\quad ,&{{ 18}})\quad 
%  (c,d)
&({{ x}}\quad ,&{{ y}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)

\bf \left( \cfrac{x+9}{2}~,~\cfrac{y+18}{2} \right)=\stackrel{\textit{midpoint}}{(14,16)}\implies 
\begin{cases}
\cfrac{x+9}{2}=14\\\\
x+9=28\\
\boxed{x=19}\\
-------\\
\cfrac{y+18}{2}=16\\\\
y+18=32\\
\boxed{y=14}
\end{cases}
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