$6 off the regular price of $40. What percent did she save?
1 answer:
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Answer:
The students have to score 0.74 standard deviations above the mean to be publicly recognized.
Step-by-step explanation:
A random variable <em>X</em> is said to have a normal distribution with parameters <em>µ</em> (mean) and <em>σ</em>² (variance).
If , then
, is a standard normal variate with mean, E (<em>Z</em>) = 0 and Var (<em>Z</em>) = 1. That is,
.
The distribution of these <em>z</em>-scores is known as the standard normal distribution.
The <em>z</em>-score is a standardized form of the raw score, <em>X</em>. It is a numerical measurement of the relationship between a value (<em>X</em>) and the mean (<em>µ</em>) in terms of the standard deviation (<em>σ</em>). A <em>z</em>-score of -1 implies that the data value is 1 standard deviation below the mean. And a <em>z</em>-score of 1 implies that the data value is 1 standard deviation above the mean.
Let <em>X</em> be defined as the scores of students at the National Financial Capability Challenge Exam.
It is provided that the students who score in the top 23% are recognized publicly for their achievement by the Department of the Treasury.
That is, P (X > x) = 0.23.
⇒
⇒
The value of <em>z</em> for this probability value is:
<em>z</em> = 0.74.
*Use a <em>z</em>-table.
Thus, the students have to score 0.74 standard deviations above the mean to be publicly recognized.
Answer:
1). System of equations- D + Q = 90 and D + 2.5Q = 175.50
2). There are 33 dimes and 57 quarters in the bank.
Step-by-step explanation:
Dylan has a bank that sorts coins as they are dropped in it.
A panel shows the total number of coins inside as well as the total value of these coins.
Let the number of dimes in the bank = D
and the number of quarters in the bank = Q
If the panel shows total number of coins = 90
Then the equation will be
D + Q = 90 -------(1)
And the panel displays the amount of the coins = $17.55
Then equation will be
0.10D + 0.25Q = 17.55 [1 Dime = $0.10 and 1 quarter = $0.25]
D + 2.5Q = 175.50 ------------(2)
Now we subtract equation (1) form equation (2)
D + 2.5Q - (D + Q) = 175.50 - 90
D + 2.5Q - D - Q = 85.5
1.5Q = 85.5
Q =
= 57
By putting Q = 57 in the equation (1)
D + 57 = 90
D = 90 - 57 = 33
Therefore, there are 33 dimes and 57 quarters in the bank.