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mrs_skeptik [129]
3 years ago
10

Critique each of the following proposed research plans. Your critique should explain any problems with the proposed research and

describe how the research plan might be improved. Include any discussion of any additional data that need to be collected. A researcher is interested in determining whether a large aerospace firm is guilty of gender bias in setting wages. To determine potential​ bias, the researcher collects salary and gender information for all the​ firm's engineers. The researcher then plans to conduct a​ "difference in​ means" test to determine whether the average salary for women is significantly less than the average salary for men. Which of the following variables are likely useful to add to the regression to control for important omitted​ variables? ​(Check all that apply​)
Mathematics
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

Explained

Step-by-step explanation:

Given that:

- A researcher is interested in determining whether a large aerospace firm is guilty of gender bias in setting wages.

According to the given info the difference in means test is too limited because it does not include the type of engineer, education level or experience. The gender with lower wages of might be reflected in the type of engineer or education level.

The research could be improved using additional data on the factors namely gender, education, education and the type of engineer.

Then, further it is recommended to construct a multiple regression where the dependent variable is a wage and the four factors are independent variables. The importance of the omited variable by the means of that the "difference in means" test in unsuitable for determining the gender bias in setting wages.

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Which set or ordered pairs represents y as a unction Or X!
Zepler [3.9K]

A relation is said to be a function when every element in the domain has one and only one distinct image in the co- domain.

In the first three options , one single element in domain has more than one image.

(-2,3), (-2, 2), (-2, 1), (-2, 0)

here -2 as an element in the domain has 3,2,1,0 has image-----> so not a function

(10, 15), (5, 1), (10, 6), (6, 10)

Here 10 , an element in the domain has 15,6 as image-----> so not a function

(-11, 2), (3,8), (3, 2), (2, 2)

Here 3, as an element in the domain has 8 and 2 as image-----> so not a function

So, OPTION D

(1,6), (2, 5), (10, 5), (-17, 8)

7 0
3 years ago
The perimeter of a triangle is 42 yards. The first side is 5 yards less than the second side, and the third side is 2 yards less
Maru [420]
Let the second side be equal to x Then the first side is x-5 The third side will be x-5-2 = x-7 Therefore you add all the following sides and equate it to 42 yards. Ie x+x+5+x-7 = 42 3x=44 X= 44/3 Therefore the second sides length is 44/3 The first sides length is 44/3 -5 = 29/3 The third side is 44/3 -7 = 23/3
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Please help me!!!! Solve for x <br> 5^x = 5^3 x 5^8
AnnZ [28]

Answer:

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Step-by-step explanation:

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GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
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Yuri [45]

Answer:

y=2/7x

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept,

y=2/7x+0

y=2/7x

4 0
3 years ago
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