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Anna11 [10]
3 years ago
11

A snail is at the bottom of a well, 115 feet deep. On day 1, it starts climbing up the side. That night it rests and slips down

one foot. It repeats this process, climbing up 3 feet each day and sliding down one foot each night until it reaches the top of the well. On what day number with the snail reach the top?
Physics
1 answer:
julia-pushkina [17]3 years ago
4 0

Answer:

Number of days needed = 57

Explanation:

Depth of well = 115 feet

Distance traveled in day = 3 feet up

Distance traveled in night = 1 feet down.

Total displacement in 1 day = 3 - 1 = 2 feet up

When the snail reaches 112 feet up, the next 3 feet up motion on day will make it reach the top.

\texttt{Days to travel 112 feet up = }\frac{112}{2}=56

After 56 days the displacement of snail is 112 feet.

On the next day it moves up by 3 feet and reaches out of well.

Number of days needed = 57

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<h2>The magnitude 24 (\dfrac{m}{s^2} ) of the acceleration of the particle when the particle is not moving.</h2>

Explanation:

Given,

A particle moving along the x-axis has a position given by

x=(24t-2.0t^3) m      ........ (1)

To find, the magnitude (\dfrac{m}{s^2} ) of the acceleration of the particle when the particle is not moving = ?

Differentiating equation (1) w.r.t, 't', we get

\dfrac{dx}{dt} =\dfrac{d((24t-2.0t^3))}{dt}

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⇒ 24-6t^{2} = 0

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\dfrac{d^2x}{dt^2} =-12t

Put t = 2, we get

\dfrac{d^2x}{dt^2} =-12(2)=24

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Two friends leave a movie theater and take different busses to the same ice cream shop. One bus takes a longer route driving on
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Therefore, the two cars have same momentum.

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What Newton discovered is that  gravity extends throughout the universe.

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