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slavikrds [6]
3 years ago
7

Which of the following is an oxidation-reduction reaction? ZnS(s) + 2O2(g) mc011-1.jpg ZnSO4(s) CaO(s) + H2O(l) mc011-2.jpg Ca(O

H)2(s) 6Li2O(s) + P4O10(g) mc011-3.jpg 4Li3PO4(s) SO2(g) + H2O(l) mc011-4.jpg H2SO3(aq)
Physics
2 answers:
Hatshy [7]3 years ago
6 0
<h3><u>Answer;</u></h3>

<em>ZnS(s) + 2O2(g) → ZnSO4(s) </em>

<h3><u>Explanation;</u></h3>
  • <em><u>Oxidation </u></em>involves the loss of electrons while<em><u> reduction </u></em>is the gaining of electrons. Oxidation-reduction reaction is a reaction which involves the gaining of electrons and loss of electrons.
  • Oxidation may also be referred to as <em><u>increase in the oxidation state </u></em>of an atom while reduction is <u><em>the decrease of oxidation state</em></u> of an atom.
  • The reaction<em> ZnS(s) + 2O2(g) → ZnSO4(s) </em>is an example of a redox reaction or what we call oxidation-reduction reaction.
  • The <u><em>oxidation number of sulfur in ZnS is -2, while the oxidation number of sulfur in ZnSO₄ is 4</em></u>. This means<em><u> sulfur has undergone oxidation.</u></em>
  • The <em><u>oxidation number of oxygen in oxygen gas is Zero, and its oxidation number in ZnSO₄ is -2,</u></em> therefore <em><u>oxygen has undergone reduction.</u></em>
aliya0001 [1]3 years ago
4 0
<span>ZnS(s) + 2O2(g) mc011-1.jpg ZnSO4(s) CaO(s) + H2O(l) </span>
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Part b)

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Part a)

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3 years ago
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