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slavikrds [6]
3 years ago
7

Which of the following is an oxidation-reduction reaction? ZnS(s) + 2O2(g) mc011-1.jpg ZnSO4(s) CaO(s) + H2O(l) mc011-2.jpg Ca(O

H)2(s) 6Li2O(s) + P4O10(g) mc011-3.jpg 4Li3PO4(s) SO2(g) + H2O(l) mc011-4.jpg H2SO3(aq)
Physics
2 answers:
Hatshy [7]3 years ago
6 0
<h3><u>Answer;</u></h3>

<em>ZnS(s) + 2O2(g) → ZnSO4(s) </em>

<h3><u>Explanation;</u></h3>
  • <em><u>Oxidation </u></em>involves the loss of electrons while<em><u> reduction </u></em>is the gaining of electrons. Oxidation-reduction reaction is a reaction which involves the gaining of electrons and loss of electrons.
  • Oxidation may also be referred to as <em><u>increase in the oxidation state </u></em>of an atom while reduction is <u><em>the decrease of oxidation state</em></u> of an atom.
  • The reaction<em> ZnS(s) + 2O2(g) → ZnSO4(s) </em>is an example of a redox reaction or what we call oxidation-reduction reaction.
  • The <u><em>oxidation number of sulfur in ZnS is -2, while the oxidation number of sulfur in ZnSO₄ is 4</em></u>. This means<em><u> sulfur has undergone oxidation.</u></em>
  • The <em><u>oxidation number of oxygen in oxygen gas is Zero, and its oxidation number in ZnSO₄ is -2,</u></em> therefore <em><u>oxygen has undergone reduction.</u></em>
aliya0001 [1]3 years ago
4 0
<span>ZnS(s) + 2O2(g) mc011-1.jpg ZnSO4(s) CaO(s) + H2O(l) </span>
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Time = (distance) / (speed)

Time = (4.12x10^16 m) / (3 x10^8 m/s)

Time = 1.37 x 10^8 seconds

Divide the seconds by 86,400 to get days. Then divide the days by 365 to get years.

Time = about 4.35 years

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Answer:

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Two uniform, solid cylinders of radius R and total mass M are connected along their common axis by a short, light rod and rest o
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Explanation:

A) To prove the motion of the center of mass of the cylinders is simple harmonic:

System diagram for given situation is shown in attached Fig. 1

We can prove the motion of the center of mass of the cylinders is simple harmonic if

a_{x} = -\omega^{2}  x

where aₓ is acceleration when attached cylinders move in horizontal direction:

<h3>PROOF:</h3>

rotational inertia for cylinders  is given as:

                                  I=\frac{1}{2}MR^{2} -----(1)

Newton's second law for angular motion is:

                                             ∑τ = Iα ------(2)

For linear motion in horizontal direction it is:

                                             ∑Fₓ = Maₓ ------ (3)

By definition of torque:

                                               τ  = RF --------(4)        

Put (4) and (1) in (2)

                                       RF=\frac{1}{2}MR^{2}\alpha

                                       RF=\frac{1}{2}MR^{2}\alpha

from Fig 3 it can be seen that fs is force by which the cylinders roll without slipping as they oscillate

So above equation becomes

                                   f_{s}=\frac{1}{2}MR\alpha------ (5)

As angular acceleration is related to linear by:

                                          a= R\alpha

Eq (5) becomes

                                    f_{s}=\frac{1}{2}Ma_{x}---- (6)

aₓ shows displacement in horizontal direction

From (3)

                                              ∑Fₓ = Maₓ

Fₓ is sum of fs and restoring force that spring exerts:

                                  \sum F_{x} = f_{s} - kx ----(7)

Put (7) in (3)

                                  f_{s} - kx  = Ma_{x}[/tex] -----(8)

Using (6) in (8)

                               \frac{1}{2}Ma_{x} - kx =Ma_{x}

                                     a_{x} = \frac{2k}{3M} x --- (9)

For spring mass system

                                  a= -\omega^{2} x ----- (10)

Equating (9) and (10)

                                  \omega^{2} = \frac{2k}{3M}

\omega = \sqrt{ \frac{2k}{3M}}

then (9) becomes

                                a_{x} = - \omega^{2}x

(The minus sign says that x and  aₓ  have opposite directions as shown in fig 3)

This proves that the motion of the center of mass of the cylinders is simple harmonic.

<h3 /><h3>B) Time Period</h3>

Time period is related to angular frequency as:

                                   T=\frac{2\pi }{\omega}

                                  T = 2\pi \sqrt{\frac{3M}{2k}

                           

 

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In an insulated vessel, a quantity of hot water at temperature T1 is mixed with a different quantity of cold water at temperatur
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Answer:Water Only

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Heat released by hot water is equal to heat gain by cold water .

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