Answer:flow velocity of the water leaving the end of the hose is 31.87 cm/s or 0.3187 m/s
Explanation:
Given that
Diameter of hose, d = 5/8 in
changing to cm becomes
1 inch =2.54 cm
5/ 8 inch=0.625 x 2.54= 1.5875cm
Volume of water filled = 2gallons
changing to cubic centimeters
1 gallon = 3785.41cm^3
2 gallons = 3785.41 x 2 =7570.82cm^3
Time, t = 2 min
60 sec= 1 min
?? sec = 2 min
= 120 secs
The volumetric flow rate of water, F is given as
F = V/t = 7570.82cm^3÷ 120 seconds
F = 63.09 cm^3/s
We Know that The volumetric flow rate is also equal the cross sectional area of pipe times the speed of flow(velocity of flow). ie
F = Av
v = F/A
Since Area A = πd^2/4
v = F/(πd^2/4)
v = 4F/πd^2
Puting the given values;
v = (4× 63.09 )/(π×1.5875²)
v = 252.36/πx 2.5202
v = 31.869 cm/s =31.87cm/s 0r 0.3187m/s
Therefore flow velocity of the water leaving the end of the hose is 31.87 cm/s or 0.3187 m/s
I’d put atmosphere.
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I'm assuming a typo here, where all of the figures are typed twice. So let the speeds of the trains be n and n+20. Then:
8n+8(n+20)=960
16n=800
n=50
n+20=70
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Answer:
it would have run 498 miles
Explanation:
if the polar bear runs 8.3 every second then multiply 8.3 times sixty to get 498
Explanation:
The vertical displacement of the wave is measured from the
equilibrium to the crest and is called the frequency.
crest to the trough and is called the amplitude.
trough to the trough and is called the wavelength.
equilibrium to the crest and is called the amplitude.
HØPÊ ĮŤ ÌŠ helpful
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