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3 years ago

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A satellite is orbiting the earth. If a payload of material is added until it doubles the satellite's mass, the earth's pull of

gravity on this satellite will double but the satellite's orbit will not be affected. A satellite is orbiting the earth. If a payload of material is added until it doubles the satellite's mass, the earth's pull of gravity on this satellite will double but the satellite's orbit will not be affected. True False

2 answers:

adelina 88 [10]3 years ago

7 0

Answer:

it is True

Explanation:

I hope this helps

Fofino [41]3 years ago

5 0

Answer:

Explanation:

True, provided that the extra mass is also already in the same orbit itself.

If the extra mass is NOT in the same orbit, it's called a collision and the orbits of both will be altered due to the changes in momentum and kinetic energy.

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The front 1.20 m of a 1,600-kg car is designed as a "crumple zone" that collapses to absorb the shock of a collision. (a) If a c

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To develop the problem it is necessary to apply the kinematic equations for the description of the position, speed and acceleration.

In turn, we will resort to the application of Newton's second law.

PART A) For the first part we look for the time, in a constant acceleration, knowing the speeds and the displacement therefore we know that,

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X = Desplazamiento

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t = Time

In this case there is no initial displacement or initial velocity, therefore

$X_f = \frac{1}{2} (V_i+V_f)t$

Clearing for time,

$t = \frac{2X_f}{(V_i+V_f)}$

$t = \frac{2*1.2}{24+0}$

$t = 0.1s$

PART B) This is a question about the impulse of bodies, where we turn to Newton's second law, because:

F = ma

Where,

m=mass

a = acceleration

Acceleration can also be written as,

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Then

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$F = m\frac{V_f-V_i}{t}$

$F = m\frac{-V_i}{t}$

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$F = -384000N$

Negative symbol is because the force is opposite of the direction of moton.

PART C) Acceleration through kinematics equation is defined as

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Weather
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a bicycle accelerates at 1 m/s² from an initial velocity of 4 m/s² for 10s. Find the distance moved by it during this interval o

BaLLatris [955]

Answer:

90 m

Explanation:

Acceleration, $a=\frac {v-u}{t}$ where v and u are final and initial velocities respectively, t is the time taken

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