Answer:
6Ω
Explanation:
The 6Ω resistor and the 3Ω resistor are in parallel.
R = 1 / (1/6 + 1/3)
R = 1 / (1/6 + 2/6)
R = 1 / (3/6)
R = 6/3
R = 2
The 8Ω resistor and the other 8Ω resistor are also in parallel.
R = 1 / (1/8 + 1/8)
R = 1 / (2/8)
R = 8/2
R = 4
This 4Ω resistance is in series with the 4Ω resistor.
R = 4 + 4
R = 8
The 2Ω resistor and the 6Ω resistor are also in series.
R = 2 + 6
R = 8
These two 8Ω resistances are in parallel.
R = 1 / (1/8 + 1/8)
R = 1 / (2/8)
R = 8/2
R = 4
Finally, this 4Ω resistance is in series with the 2Ω resistance we found earlier.
R = 4 + 2
R = 6
The total equivalent resistance is 6Ω.
Answer: B. The south magnetic pole attracts the north pole of another magnet.
Explanation:
The correct statement below about the interaction between magnets, magnetic materials and charges is that the south magnetic pole attracts the north pole of another magnet.
We should note that a magnet typically consists of two poles which are the North Pole and the South pole. The opposite poles doesn't repel each other but attracts each other while same pole repels one another.
In this case, the North Pole will attract the South Pole while same magnetic piles repel e.g the North Pole will repel the North Pole.
Answer: Hey
B an encyclopedia entry about an experiment
A primary resource is information that was documented during an event that was written about.
Please wait tell you get another answer because im not sure about this
Answer:
The potential energy of the rock = 10.5 kN
Explanation:
Mass of rock = 25 kg
Acceleration due to gravity = 10 m/s²
Height = 42 m
Potential energy, PE = mgh, where m is the mass, g is acceleration due to gravity and h is the height.
PE = 25 x 10 x 42 = 10500 N = 10.5 kN
The potential energy of the rock = 10.5 kN
Answer:
The height is 
A circular hoop of different diameter cannot be released from a height 30cm and match the sphere speed because from the conservation relation the speed of the hoop is independent of the radius (Hence also the diameter )
Explanation:
From the question we are told that
The height is 
The angle of the slope is 
According to the law of conservation of energy
The potential energy of the sphere at the top of the slope = Rotational kinetic energy + the linear kinetic energy

Where I is the moment of inertia which is mathematically represented as this for a sphere

The angular velocity
is mathematically represented as

So the equation for conservation of energy becomes
![mgh_s = \frac{1}{2} [\frac{2}{5} mr^2 ][\frac{v}{r} ]^2 + \frac{1}{2}mv^2](https://tex.z-dn.net/?f=mgh_s%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5B%5Cfrac%7B2%7D%7B5%7D%20mr%5E2%20%5D%5B%5Cfrac%7Bv%7D%7Br%7D%20%5D%5E2%20%2B%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![mgh_s = \frac{1}{2} mv^2 [\frac{2}{5} +1 ]](https://tex.z-dn.net/?f=mgh_s%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E2%20%5B%5Cfrac%7B2%7D%7B5%7D%20%2B1%20%5D)
![mgh_s = \frac{1}{2} mv^2 [\frac{7}{5} ]](https://tex.z-dn.net/?f=mgh_s%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E2%20%5B%5Cfrac%7B7%7D%7B5%7D%20%5D)
![gh_s =[\frac{7}{10} ] v^2](https://tex.z-dn.net/?f=gh_s%20%3D%5B%5Cfrac%7B7%7D%7B10%7D%20%5D%20v%5E2)

Considering a circular hoop
The moment of inertial is different for circle and it is mathematically represented as

Substituting this into the conservation equation above
![mgh_c = \frac{1}{2} (mr^2)[\frac{v}{r} ] ^2 + \frac{1}{2} mv^2](https://tex.z-dn.net/?f=mgh_c%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%28mr%5E2%29%5B%5Cfrac%7Bv%7D%7Br%7D%20%5D%20%5E2%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E2)
Where
is the height where the circular hoop would be released to equal the speed of the sphere at the bottom



Recall that 


Substituting values
