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lana [24]
3 years ago
9

Patty made a banner that has an area of 96 square inches. The length and width of the banner are whole numbers. The length is 6

times greater than the width. What are the dimensions of the​ banner?
Mathematics
1 answer:
Katen [24]3 years ago
4 0

Answer:

The length of the banner is 24 inches and its width is 4 inches.

Step-by-step explanation:

Let the length of the banner be L.

Let the width of the banner be W.

The length is 6 times greater than the width. This means that:

L = 6W

The area of the banner is:

A = L * W = 6W * W = 6W^2

The are of the banner is 96 square inches. This implies that:

6W^2 = 96

=> W^2 = 96 / 6 = 16

W = \sqrt{16}

W = 4 inches

The length, L, will be:

L = 6 * 4 = 24 inches

The length of the banner is 24 inches and its width is 4 inches.

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6x-5y=15 x=y+3 find x and y
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Answer:

(0, -3)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

6x - 5y = 15

x = y + 3

<u>Step 2: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

  1. Substitute in <em>x</em>:                                                                                                  6(y + 3) - 5y = 15
  2. Distribute 6:                                                                                                    6y + 18 - 5y = 15
  3. Combine like terms:                                                                                        y + 18 = 15
  4. [Subtraction Property of Equality] Subtract 18 on both sides:                     y = -3

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Define original equation:                                                                               x = y + 3
  2. Substitute in <em>y</em>:                                                                                                   x = -3 + 3
  3. Add:                                                                                                                   x = 0
7 0
3 years ago
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