Answer:
24mm
Step-by-step explanation:
since it's a similar triangle, we solve;
EH/EG=DH/DG
EH=56mm;
EG=44.8mm;
DH=35mm;
DG=X+4.
Fix them,
56/44.8=35/x+4
cross multiply
56(x+4)=35×44.8
56x+224=1,568
collect the like term
56x=1,344
divide via by 56
56x/56=1344/56
x=24mm
Check/ verify
EH/EG=DH/DG
56/44.8=35/24+4
56/44.8=35/28
CROSS MULTIPLY OVER THE EQUAL SIGN.
56×28=35×44.8
1,568=1,568
THAT'S CORRECT.
Answer:
Wouldn't the answer be C) Positive Integers?
Step-by-step explanation: Because the complement of a set include all of the elements not included in the indicated set. I hope I'm making some sense. :)
All you have to do is divide 92 by 6 and you get your answer. The remainder is the spaces she'll have left
Strange question, as normally we would not calculate the "area of the tire." A tire has a cross-sectional area, true, but we don't know the outside radius of the tire when it's mounted on the wheel.
We could certainly calculate the area of a circle with radius 8 inches; it's
A = πr^2, or (here) A = π (8 in)^2 = 64π in^2.
The circumference of the wheel (of radius 8 in) is C = 2π*r, or 16π in.
The numerical difference between 64π and 16π is 48π; this makes no sense because we cannot compare area (in^2) to length (in).
If possible, discuss this situatio with your teacher.
