12x2-7=6-2x2+2
14x^2-15=0
a=14 , b =0 , c=-15
0^2-4x14x(-15) =
840
1) 5.1
2)7.9
3) 4
4)20
5)8.9
6) 4.2
7)5.2
8)15
I'am somewhat confident that some are right because iam not sure your suppose to round the nearst tenth
Since 6 is positive, it's (x+blank)^2
6/2=3, and (x+3)^2 = x^2+6x+9. We have x^2+6x-2, so we have to add 9 to both sides to get (x+3)^2-2=9, then subtract 9 from both sides to get
(x+3)^2-11=0, or (x+3)^2=11. Square root both sides to get x+3=sqrt(11), and x=sqrt(11)-3, which is approximately 0.32
The correct answer is the last set of numbers
