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3 years ago

Please help me with this question

Mathematics

1 answer:

lara31 [8.8K]3 years ago

5 0

Answer:

ghghjhjghjghghjghghj

Step-by-step explanation:

jghjghjghjghj

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Sin(0)= cos(6) what is the value of 0?

Licemer1 [7]

We need to find Ο for : sin(Ο)= cos(6)

We know that:

cos θ =sin (90 - θ), so if we call θ = 6 then O will be:

O = 90 - θ

O = 90 - 6

8 0

3 years ago

First person to answer 10 points

Assoli18 [71]

It’s the third one. Hopefully this helped

8 0

3 years ago

I really need help guys can some one plz help me it's for 10 points

11111nata11111 [884]

Answer:

$\sqrt{8}----- 2units,2units$

$\sqrt{7} ------\sqrt{5}units,\sqrt{2}units$

$\sqrt{5}-------1unit,2units$

$3------2units, \sqrt{5}units$

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

$Formula: c^2=a^2+b^2$

1. $a=\sqrt{5}, b=\sqrt{2}$

Plug this into the formula.

$c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }$

The square here eliminates the roots.

$c=\sqrt{5+2}\\ c=\sqrt{7}$

2. $a=\sqrt{3}, b=4$

$c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}$

3. $a=2, b=\sqrt{5}$

$c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3$

4. $a=2, b=2$

$c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}$

5. $a=1, b=2$

$c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}$

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3 years ago

What is the volume of a right cylinder with a base diameter of 6m and a height of 5m

SOVA2 [1]

Answer:

V≈141.37m³

<h2>explanation :</h2>

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3 years ago

Which answer is the equation of the line represented in function notation?

algol [13]

That has a y intercept at y=-1. For every one block to the right we go three blocks up, so that's a slope of 3/1=3. So in slope-intercept form our equation is

y = 3 x - 1

Answer: third choice

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3 years ago

Read 2 more answers