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3 years ago

What is the area of the trapezoid?

Mathematics

2 answers:

Setler [38]3 years ago

8 0

Your answer is b: 24

Artemon [7]3 years ago

8 0

Answer: The correct option is (B) 24 square units.

Step-by-step explanation: We are given to find the area of the trapezium in the figure.

The AREA of a TRAPEZIUM with lengths of parallel sides as 'a' and 'b' units and height 'h' units is given by the formula:

$A=\dfrac{1}{2}(a+b)h.$

In the given trapezium, we have

lengths of the parallel sides are

a = 4 units and b = 8 units,

and height, h = 4 units.

Therefore, the area of the given trapezium is

$A\\\\\\=\dfrac{1}{2}(a+b)h\\\\\\=\dfrac{1}{2}\times(4+8)\times 4\\\\\\=12\times 2\\\\=24~\textup{sq. units.}$

Thus, the area of the trapezium is 24 square units.

Option (B) is correct.

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mario62 [17]

Answer:

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Step-by-step explanation:

If one root is -7i, another root must be 7i. You can't just have one root with i. The other roos is √2, so there are 3 roots.

x = -7i is one root,

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(x - 7i) = 0 is the factor

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(x - √2) = 0 is the factor

So the factors are...

(x + 7i)(x - 7i)(x - √2) = 0

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3 years ago

This problem is only for smart kids, all people who dont do it r babies

Phantasy [73]

Answer:

Step-by-step explanation:

∠DAC ≅ ∠ACB because they are opposite interior angles where transversal AC crosses parallel lines BC and AD.

∠DAC ≅ ∠CAB because they are corresponding angles of the similar triangles ΔABC and ΔACD.

Hence ∠ACB ≅ ∠CAB and ΔABC is isosceles with side lengths both being 9. The corresponding side lengths of ΔACD are 12, meaning the base of ΔABC, segment AC, is 12. The scale factor of ΔACD to ΔABC is then 12:9 = 4:3, so the base AD of ΔACD is (4/3)×12 = 16.

So, the side lengths of the trapezoid are ...