Given: Angle 2 and Angle 3 are a linear pair. Angle 3 and Angle 4 are a linear pair. Prove Angle 2 is congruent to Angle 4.

1 answer:

6 0

Reason 2 is that they are linear, so they form 180 degrees, which makes them supplementary. Reason 3 is that they are both 180 - angle 3. I think. I'm not sure about reason 3.

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Could someone help me out ill mark brainliest

zlopas [31]

Step-by-step explanation:

1. The first graph has a negative slope (increases to the left) and has a y-intercept of 3. So, the equation of the line would be y = -2x + 3.

2. The second graph has a positive slope (increases to the right) and has a y-intercept of -3. Therefore, the equation of the line would be y = 2x - 3.

3. The third graph has a negative slope and has a y-intercept of -3. So, we can say that the equation of the line would be y = -2x - 3.

4. The fourth graph has a positive slope and a y-intercept of 3. Therefore, the equation of the line would be y = 2x + 3.

8 0

3 years ago

Read 2 more answers

(6 8/25 ÷(−1)−(−0.8)·(−0.1))÷(−0.25÷1.25−1 3/5 ÷(−5 1/3 ))

const2013 [10]

Answer:

-64

Step-by-step explanation:

Given expression

$\left(6 \dfrac{8}{25}\div (-1)-(-0.8)\cdot (-0.1)\right)\div\left (-0.25\div 1.25-1 \dfrac{3}{5} \div\left(-5 \dfrac{1}{3} \right)\right)$

Perform all multiplications and divisions:

$6\dfrac{8}{25}\div (-1)=-6\dfrac{8}{25}\\ \\(-0.8)\cdot (-0.1)=0.08\\ \\-0.25\div 1.25=-\dfrac{0.25}{1.25}=-\dfrac{25}{125}=-\dfrac{1}{5}\\ \\1\dfrac{3}{5}\div \left(-5\dfrac{1}{3}\right)=-\dfrac{8}{5}\cdot \dfrac{3}{16}=-\dfrac{3}{10}$