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Nata [24]
3 years ago
5

One teacher wants to give each student 6/7 of a slice of pizza .if the teacher has 6 slices of pizza , then how many students wi

ll she be able to hand out pizza to ?
Mathematics
1 answer:
jek_recluse [69]3 years ago
7 0

Answer:

Step-by-step explanation:

6 / (6/7) =

6 * 7/6 =

42/6 =

7 <=== 7 students can get some

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A fireman's ladder leaning against a house makes an angle of 50° with the ground. How long is the ladder if the ladder is 8 feet
antoniya [11.8K]

The ladder would be 12.4 feet hope that helps

5 0
3 years ago
which of the following is a lab hazard A. laser radiation hazard B. animal hazard C. Explosive hazard D. chemical
QveST [7]

Answer:

c maybe

Step-by-step explanation:

4 0
3 years ago
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Find the midpoint of the segment with the following endpoints.<br> (10,2) and (5, -7)
Sati [7]

Answer:

(7.5 , -2.5)

Step-by-step explanation:

Sub the values into this formula

4 0
3 years ago
​Ramona's Garage charges the following labor rates. All customers are charged for at least 0.5 hr.
algol13

Answer:

a. The linear function is given by,

y = 60x + 30  [y is in $ and x is in hour and x ≥ 0.5]

  = 60 [for x < 0.5]

b. The total cost of the repair job is,  $ 675 .

Step-by-step explanation:

Let, the linear function describing garage charge( y in $) and no. of hours of repair job ( x in hour) be,

y = mx + c    [for x ≥ 0.5]  -----------(1)

where, m is the slope of the line and c is the y intercept.

Now ,

m = \frac {90 - 60}{1 - 0.5}

  = 60  ----------------(2)

Now, putting the value of m and the point (x,y) = (0.5, 60) in (1), we get,

60 = 60 \times 0.5 + c $

⇒ c = 30 ----------------- (3)  

Hence, the linear function is given by,

y = 60x + 30  [y is in $ and x is in hour and x ≥ 0.5] ------------(4)

  = 60 [for x < 0.5]

Now, putting

x = 4 hr 15 min

= 4\dfrac {15}{60} hour

= 4.25 hour in (4), we get,

y = 60 \times 4.25 + 30  [in $]

= $ 285

So, the total cost of the repair job,

= $ (285 + 390)

= $ 675

3 0
3 years ago
"What is the probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice? Assume you’re throwing a single d
dem82 [27]

Answer:

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

Step-by-step explanation:

For each throw, there are only two possible outcomes. Either it is a '3', or it is not. This means that we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

There are 6 possible outcomes for the dice. This means that the probability that it is a '3' is \frac{1}{6} = 0.167

There are 10 throws, so n = 10.

Probability of throwing AT LEAST two ‘3’s on the dice?

Either you throw less than two, or you throw at least two. The sum of the probabilities of these events is 1. So

P(X < 2) + P(X \geq 2) = 1

P(X \geq 2) = 1 - P(X < 2).

In which

P(X < 2) = P(X = 0) + P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.167)^{0}.(0.833)^{10} = 0.1609

P(X = 1) = C_{10,1}.(0.167)^{1}.(0.833)^{9} = 0.3225

So

P(X < 2) = P(X = 0) + P(X = 1) = 0.1609 + 0.3225 = 0.4834.

Finally:

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.4839 = 0.5161.

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

5 0
3 years ago
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