You pick a card at random. Without putting the first card back, you pick a second card at random. 1 2 3 4 5 6 7 8 What is the pr
obability of picking a 1 and then picking an odd number? Write your answer as a percentage rounded to the nearest tenth.
1 answer:
Answer:
%12.8 for the card withe the number 1
%37.8 for the odd number
Step-by-step explanation:
you only have a number one card so thats 1/8 and when converted to percentage is %12.8
theres 3 odd numbers not counting the 1 so thats 3/8 coverted to percent is %37.8
to find percentage to multiply the Numerator by Denominator and multiply by 100
Feel free to ask for more help :)
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I think it's 2.56
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