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Eduardwww [97]
3 years ago
6

Oscar drew the image of a

Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0

Answer:

When we have a point (x, y) and we do a reflection over a given line, we know that the new point (x', y') will be at the same distance from the line as our initial point (x,y).

Now, in this case, we have a reflection over the line y = -1. (this line is parallel to the x-axis)

But in the image, we can see that the reflected triangle is drawn in the other side of the y-axis, this means that the reflection was made in a line parallel to the y-axis.

Then the mistake that Oscar did is that he reflected over the wrong line, seems that he reflected the triangle over the line x = -1 instead of the line y = -1.

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Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}

8 0
3 years ago
Order these numbers from least to greatest <br> {13.7, 13,7/100 –13,17/100 –13.2}
Yuri [45]

Answer:

{13.7, 13,7/100 –13,17/100 –13.2}

Step-by-step explanation:

4 0
2 years ago
One angle of a right triangle measures 8°. What is the measure of the other acute angle?
Ivahew [28]

Answer:

  82°

Step-by-step explanation:

The acute angles in a right triangle are complementary. The other one is ...

  90° -8° = 82°

5 0
2 years ago
PLEASE HELP! 8 POINTS!! Find the value
Pepsi [2]

Answer:

-sqrt(3)/2

Step-by-step explanation:

Use double angle identity for sin(2x)

sin(2x)=2sin(x)cos(x)

We are given sin(x)=-1/2 so we already have so far that:

sin(2x)=2(-1/2)cos(x)

sin(2x)=-1*cos(x)

We just need to find cos(x).  

x is in the fourth quadrant so cosine will be positive there

knowing the unit circle we should know that if sin(x)=-1/2 then cos(x)=sqrt(3)/2 while in 4th quadrant.

So the answer is sin(2x)=-1*sqrt(3)/2=-sqrt(3)/2

5 0
3 years ago
(5^2)^3 x(3^0 x 5^-3)​
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easy

10^3x(0)

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