Answer:
A
Step-by-step explanation:
Distance between 2 points
☆ (x₁, y₁) is the first coordinate while (x₂, y₂) I'd the second coordinate.
Length of RS
![= \sqrt{ {[ - 1 -( - 4)] }^{2} + (9 - 1)^{2} } \\ = \sqrt{( - 1 + 4)^{2} + 8^{2} } \\ = \sqrt{ {3}^{2} + 64 } \\ = \sqrt{73} \\ = 8.54 \: (3 \: s.f.)](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B%20%7B%5B%20-%201%20-%28%20-%204%29%5D%20%7D%5E%7B2%7D%20%20%2B%20%289%20-%201%29%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%28%20-%201%20%2B%204%29%5E%7B2%7D%20%20%2B%208%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%20%7B3%7D%5E%7B2%7D%20%20%2B%2064%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B73%7D%20%20%5C%5C%20%3D%208.54%20%5C%3A%20%283%20%5C%3A%20s.f.%29)
Thus, RS is about 8.5 units.
Answer:
32
Step-by-step explanation:
Plug in 4 for c.
(c³)/2 = (4³)/2
First, solve the parenthesis, then divide. Multiply:
4³ = 4 * 4 * 4 = 16 * 4 = 64
Next, divide:
64/2 = 32
32 is your answer.
~
When the first number increases by one the second number is added by 4's. So from the first part to the second it added 4 then from the 2nd to the 3rd it skips adding 8 to then just add 12. Then from the 3rd to the 4th it skips adding 16 and adds 20. So the next set of numbers would be (4,64) because it skips adding the 24 and adds the 28.
Hope this helps and is not to confusing :)
Answer:
Step-by-step explanation:
![\sf 3(t+3)+5(3+2t)-76 = 0\\\\Expanding \ Parenthesis\\\\3t + 9 + 15 + 10t -76 = 0\\\\13t + 24 -76 = 0\\\\13t - 52 = 0\\\\Add \ 52 \ to \ both \ sides\\\\13t = 52\\\\Dividing\ both\ sides\ by\ 13\\\\t = 52/13\\\\t = 4\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%203%28t%2B3%29%2B5%283%2B2t%29-76%20%3D%200%5C%5C%5C%5CExpanding%20%5C%20Parenthesis%5C%5C%5C%5C3t%20%2B%209%20%2B%2015%20%2B%2010t%20-76%20%3D%200%5C%5C%5C%5C13t%20%2B%2024%20-76%20%3D%200%5C%5C%5C%5C13t%20-%2052%20%3D%200%5C%5C%5C%5CAdd%20%5C%2052%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C13t%20%3D%2052%5C%5C%5C%5CDividing%5C%20both%5C%20sides%5C%20by%5C%2013%5C%5C%5C%5Ct%20%3D%2052%2F13%5C%5C%5C%5Ct%20%3D%204%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
