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kykrilka [37]
3 years ago
8

Need help with geometric sequence quick 30 points!!!!

Mathematics
1 answer:
hram777 [196]3 years ago
7 0

The explicit formula for given geometric sequence is:

a_n = 6 . 5^{n-1}

Step-by-step explanation:

Given geometric sequence is:

6,30,150,750....

First of all we will find the common ratio.

Common ratio is the ratio between two consecutive terms of a geometric sequence

In the given sequence

a1 = 6

a2 = 30

a3 = 150

a4 = 750

Now

r=\frac{a_2}{a_1} = \frac{30}{6} = 5\\r=\frac{a_3}{a_2} = \frac{150}{30} = 5

The explicit formula for geometric sequence is:

a_n = a_1 . r^{n-1}

Putting the values of a1 and r

a_n = 6 . 5^{n-1}

Keywords: Geometric sequence

Learn more about geometric sequence at:

  • brainly.com/question/2367554
  • brainly.com/question/2670657

#LearnwithBrainly

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y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form ay''+by'+cy=0.

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\left ( r^2+r+1 \right )e^{rt}=0

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{ we know that for equation ax^2+bx+c=0, roots are of form x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} }

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y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}

For two complex roots r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta, the general solution is of form y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )

i.e y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Applying conditions y(0)=1 on e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right ), c_1=1

So, equation becomes y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

On differentiating with respect to t, we get

y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )

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y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

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