That is an arithmetic sequence of the form:
a(n)=2n-1
Now the sum of an arithmetic sequence is just the average of the first and last terms times the number of terms...
We know the first term is 1, let's find the last term...
a(1000)=2(1000)-1=1999
So the sum of that sequence is:
1000(1999+1)/2
1,000,000
The equation of parabola is

.
The canonical equation of parabola is

and this parabola has branches that go in positive direction of x-axis.
Since in your equation x is changed to y and y to x, then the <span>branches of the parabola go in positive y-axis direction, the vertex is placed at the origin.
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Answer:
Below
Step-by-step explanation:
To prove that the diagonals bisect each other we should prove that they have a common point.
From the graph we notice that this point is E.
ABCD is a paralellogram, so E is the midpoint of both diagonals.
●●●●●●●●●●●●●●●●●●●●●●●●
Let's start with AC.
● A(0,0)
● C(2a+2b,2c)
● E( (2a+2b+0)/2 , (2c+0)/2)
● E ( a+b, c)
●●●●●●●●●●●●●●●●●●●●●●●●
BD:
● B(2b,2c)
● D(2a,0)
● E ( (2a+2b)/2 , 2c/2)
● E ( a+b ,c)
●●●●●●●●●●●●●●●●●●●●●●●●●
So we conclude that the diagonals bisect each others in E.
Answer:
Yes, I do for my Spanish class!
Do you have any questions about it?