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Elis [28]
3 years ago
11

Solve using elimination or substitution method

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

\left\{\begin{array}{ccc}y=\dfrac{2}{3}x+3\\2x-3y=-9\end{array}\right\\\\\text{substitute}\ y=\dfrac{2}{3}x+3\ \text{to the second equation}\\\\2x-3\left(\dfrac{2}{3}x+3\right)=-9\qquad|\text{use distributive property}\\\\2x+(-3)\left(\dfrac{2}{3}x\right)+(-3)(3)=-9\\\\2x-2x-9=-9\qquad|\text{add 9 to both sides}\\\\2x-2x=0\\\\0=0\qquad TRUE\\\\Answer:\ \text{Infinitely many solutions}\\\\\left\{\begin{array}{ccc}x\in\mathbb{R}\\y=\dfrac{3}{2}x+3\end{array}\Rightarrow\left(x,\ \dfrac{2}{3}x+3\right)\right

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Let the number be x

<u>Then we have the equation</u>

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9.4\:\mathrm{cm},\\9.4\:\mathrm{cm},\\29.6\:\mathrm{cm},\\29.6\:\mathrm{cm}

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A kite consists of two pairs of congruent adjacent sides. Therefore, we have the following equation:

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Solving, we get:

2x+8x-16=78,\\10x=94,\\x=\fbox{$9.4\:\mathrm{cm}$}.

Plugging in x=9.4 into 4x-8, we get:

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