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Kamila [148]
3 years ago
15

Work out the Highest Common Factor of 63 and 105.

Mathematics
2 answers:
Firlakuza [10]3 years ago
5 0

Answer:

21.

Step-by-step explanation:

(self-explanatory)

I hope this helps, have a nice day.

eduard3 years ago
5 0
Is is 7 I’m not sure
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Step-by-step explanation:

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A point charge q1 = 3.30nC is located on the x-axis at x= 1.90m , and a second point charge q2= -6.40 nC is on the y-axis at y=
Dahasolnce [82]

Answer:

Step-by-step explanation:

charge q1 is placed at x = 1.90 m and the charge q2 is placed at y = 1.15 m

here, the charge enclosed in a sphere is zero as the radius of sphere is 0.625 m which is less than the x = 1.90 m and y = 1.15 m. So by the Gauss's theorem,

\phi =\frac{q}{\epsilon _{0}}

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3 0
3 years ago
Approximately 85% of persons age 70 to 84 live in their own household and are income-qualified for home purchases.
miv72 [106K]

Answer:

The probability that exactly two of the four live in their own household and are income-qualified is  = .0975

Step-by-step explanation:

Given -

Approximately 85% of persons age 70 to 84 live in their own household and are income-qualified for home purchases.

Probability of sucess ( p ) = 85% =.85

Probability of failure ( q ) = 1 - .85 =.15

n = 4

From combination of n events taking r sucess we use binomial distribution

P(X = r) = \binom{n}{r}p^{r}q^{n-r}

where , r = 2

the probability that exactly two of the four live in their own household and are income-qualified is =

P(X = 2) = \binom{4}{2}0.85^{2}0.15^{4 - 2}

                = \frac{4!}{(2!)(2!)} \times 0.7225  \times .0225

                 = 6 \times 0.7225  \times .0225

                 = .0975

4 0
3 years ago
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