Question

An experiment for a chemical reaction involves mixing 1 teaspoon of yeast with 14 cup of hydrogen peroxide. ​Delray wants to do the same experiment with larger amounts of the two ingredients. He use 112 cups of hydrogen peroxide and needs to keep the same ratio of yeast to hydrogen peroxide. Note that there are 48 teaspoons in 1 cup. ​ How much yeast, in cups, should Delray mix with this amount of hydrogen peroxide?

Answer 1

Answer:

Derlay will mix one-sixth of a cup with 112 cups of hydrogen peroxide.

Step-by-step explanation:

We are given the following in the question:

48 teaspoons = 1 cup

A chemical reaction involves mixing 1 teaspoon of yeast with 14 cup of hydrogen peroxide.

Thus, the ratio of yeast to hydrogen peroxide in teaspoons

$\dfrac{\text{Yeast}}{\text{Hydrogen Peroxide}} = \dfrac{1}{14\times 48} = \dfrac{1}{672}$

112 cups of hydrogen peroxide are used.

Thus, we can write:

$\dfrac{1}{672} = \dfrac{\text{Teaspoons of yeast}}{112\times 48}\\\\\text{Teaspoons of yeast} = \dfrac{112\times 48}{672}\\\\\text{Teaspoons of yeast} = 8\\\\\text{Cups of yeast} = \dfrac{8}{48} = \dfrac{1}{6}$

Thus, Derlay will mix one-sixth of a cup with 112 cups of hydrogen peroxide.